Make regular expression Python

Question

I cannot deal with the conditions in regular expressions. I need to find everything:

<script type="text/javascript">9089089089</script>
<script>9089089089</script>

Example:

<script type="text/javascript" src="python_files/py_dict.js"></script>

My regex is not working properly. Please tell me how to do it?

re.compile(r'<script.*(?<!src$).*?>(.*)</script>')

I need to find all the <script> tags that do not contain the src attribute and display the code that is inside the tag.

<script>If the condition is true, get between the tag</script> — Strelok2014Strelok
– Strelok2014Strelok, Commented May 23, 2015 at 16:16
I have no idea what you are trying to extract. Can you actually add what you want as output? — Padraic Cunningham
– Padraic Cunningham, Commented May 23, 2015 at 16:19
Do you want to just get all the attribute names and values in the script tag if there is no src attribute inside it? Please just add expected output to the question. — Wiktor Stribiżew
– Wiktor Stribiżew, Commented May 23, 2015 at 16:20

Wiktor Stribiżew · Accepted Answer · 2015-05-23 17:04:54Z

1

If you insist on a regex-based solution:

(?s)<script\b((?:(?!src).)*?)>(.*?)</script>

Python code:

import re
p = re.compile(r'(?s)<script\b((?:(?!src).)*?)>(.*?)</script>')
test_str = "<script type=\"text/javascript\" src=\"python_files/py_dict.js\"></script>\n<script type=\"text/javascript\">9089089089</script>\n<script>9089089089</script>"
print [(x.group(1), x.group(2)) for x in re.finditer(p, test_str)]

edited May 23, 2015 at 17:04

answered May 23, 2015 at 16:30

Wiktor Stribiżew

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Padraic Cunningham · Accepted Answer · 2015-05-23 16:32:55Z

1

You can use BeautifulSoup to find the script tags setting src=False:

from bs4 import BeautifulSoup
soup = BeautifulSoup(html)

print(soup.find_all("script", src=False))

It will return the script tags without the src attribute:

import  requests
r  = requests.get("http://stackoverflow.com/questions/30414867/make-regular-expression-python/30414987#30414987")
from bs4 import BeautifulSoup

soup = BeautifulSoup(r.content)
print(set(soup.find_all("script")).difference(soup.find_all("script", src=False)))
{<script src="//ajax.googleapis.com/ajax/libs/jquery/1.7.1/jquery.min.js"></script>, <script src="//cdn.sstatic.net/Js/stub.en.js?v=f07e1c0b90d5"></script>}

edited May 23, 2015 at 16:32

answered May 23, 2015 at 16:25

Padraic Cunningham

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2 Comments

Padraic Cunningham Over a year ago

@Strelok2014Strelok, why can't you use BeautifulSoup, is this homework?

Strelok2014Strelok Over a year ago

I am developing a portable app, I need a minimum of dependencies, and to parse the tags 3, BeautifulSoup pretty big ...

Static Void · Accepted Answer · 2015-05-23 16:31:30Z

0

I agree with the other answers that there is probably a python package that will work more elegantly for your application. However, if you really want to use a regular expression, just look for the script tags:

re.compile(r'<script>(.*)</script>')

When you do a re.search (or re.match) will return None if there's an src attribute in the line.

answered May 23, 2015 at 16:31

Static Void

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