How to xor hex value in Python (1 bit answer)

Question

lets say i have the following variable data=0xab12cd30 i would like to get the xor over the 32 bits (for example in verilog ^data)

for example (giving 8bit examples)

data = 0x11 -> result should be 0

data = 0x10 -> result shoule be 1

data = 0x21 -> result should be 0

data = 0x23 -> result should be 1

What is the easiest way? Using Python 2.4.3

Stefan Pochmann · Accepted Answer · 2015-06-03 20:33:23Z

2

Easiest? Maybe this:

bin(data).count('1') % 2

Demo:

>>> for data in 0x11, 0x10, 0x21, 0x23:
        print bin(data).count('1') % 2

0
1
0
1

Edit: If using an awfully old Python that doesn't have bin, here's a do-it-yourself solution:

for data in 0x11, 0x10, 0x21, 0x23:
    xor = 0
    while data:
        xor ^= data & 1
        data >>= 1
    print xor

Edit 2: A faster and more tricky solution:

for data in 0x11, 0x10, 0x21, 0x23:
xor = 0
while data:
    xor ^= 1
    data &= data - 1      # deletes the last 1-bit
print xor

answered Jun 3, 2015 at 20:26

Stefan Pochmann

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3 Comments

Hmm, i dont have the bin method (Version 2.4.3)... i dont mind to iterate over each bit, by how do i do it?

@Jonathan Ugh... nobody should still be using such an old version :-). But ok, I added another solution to my answer.

@Jonathan And now I added another, less easy but faster and more interesting one.