PHP preg_match: escaping { and }

Question

I am facing a little problem. My string is From {start} to {end} and I want to validate it using preg_match() to avoid illegal chars.

preg_match("/^[a-zA-Z\{\} ]{1,}$/",$var)

The point is the escape for { and }.

thanks :)

cletus · Accepted Answer · 2010-06-20 03:48:47Z

1

You don't need to escape curly braces inside the square brackets:

preg_match('!^[a-zA-Z{} ]+$!', $var);

If you need to escape characters, just put a backslash (\) before them. Note: if you're using a double quoted string, you may need to escape the backslashes from interpretation there. For example:

'\t' matches a tab character;
"\t" is a tab character; and
"\\t" is equivalent to '\t'.

answered Jun 20, 2010 at 3:48

cletus

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1 Comment

Michele Over a year ago

mmm, ok i actually understand the problem is that string is passed by get.

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