python string substitution

Question

Is there a simple way of passing a list as the parameter to a string substitution in python ? Something like:

w = ['a', 'b', 'c']

s = '%s\t%s\t%s\n' % w

Something similar to the way dictionaries work in this case.

Amnon · Accepted Answer · 2010-06-21 12:37:40Z

11

Just convert the list to a tuple:

w = ['a', 'b', 'c']
s = '%s\t%s\t%s\n' % tuple(w)

answered Jun 21, 2010 at 12:37

Amnon

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2 Comments

Amnon Over a year ago

And of course, as fabe said, you can just use a tuple directly.

hyperboreean Over a year ago

It depends from where that data is coming from :-), but yes, theoretically it's possible.

Fabian Barkhau · Accepted Answer · 2010-06-21 12:49:34Z

5

use a tuple instead of a list

w = ('a', 'b', 'c')
s = '%s\t%s\t%s\n' % w

using a dict also works

w = { 'Akey' : 'a', 'Bkey' : 'b', 'Ckey' : 'c' }
s = '%(Akey)s\t%(Bkey)s\t%(Ckey)s\n' % w

http://docs.python.org/release/2.5.2/lib/typesseq-strings.html

edited Jun 21, 2010 at 12:49

answered Jun 21, 2010 at 12:40

Fabian Barkhau

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Comments

Garren S · Accepted Answer · 2015-01-06 18:38:17Z

1

It's unnecessary to use a tuple instead of a list when string's join can build the string using a list for you.

w = ['a', 'b', 'c'] '\t'.join(w) + '\n' # => 'a\tb\tc\n'

edited Jan 6, 2015 at 18:38

answered Jan 5, 2015 at 20:52

Garren S

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using a dict also works

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