Numeric literals in Java - octal? [duplicate]

Question

Here is some code in java on datatypes:

class Test
{
    public static void main(String args[])
    {
        int i = -0777;
        System.out.println(i);
    }
}

The output of the above code is -511

If the code is changed to :

class Test
{
    public static void main(String args[])
    {
        int i = -777;
        System.out.println(i);
    }
}

The output is -777.

Why is the output differing??? What are the calculations done behind this code???

I would upvote this question, but the title is way too general and unspecific. — SamTebbs33
– SamTebbs33, Commented Jun 22, 2015 at 10:40
This question has nothing to do with data types. It is about numeric literals. — user207421
– user207421, Commented Jun 22, 2015 at 10:47

Eran · Accepted Answer · 2015-06-22 10:35:52Z

8

-0777 is treated by the compiler as an octal number (base 8) whose decimal value is -511 (-(64*7+8*7+7)). -777 is a decimal number.

answered Jun 22, 2015 at 10:35

Eran

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3 Comments

xrisk Over a year ago

what happens if I input “-077” via STDIN?

Kayaman Over a year ago

@RishavKundu "-077" is a String. There are numerous ways you can interpret/parse it.

Eran Over a year ago

@RishavKundu That would depend on how you read it from STDIN. For example - Scanner sc = new Scanner (System.in); System.out.println (sc.nextInt ()); will print -77 if you type in -077.

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