How to use a command's return value with pipe as a variable in batch file

Question

I want to extract a file in in windows, right after search for it, like this:

7z [args] | ls | grep filename

In my windows batch script, its:

7z [args] | dir /B | findstr filename

the search alone works perfectly like in linux, but i just cant pass it forward to a variable, or straight to 7z as an input.

I tried

pipe from the left
pipe from the right
for /f "delims=" %%a in ('dir /B ^| findstr onboard.zip') do @set Value=%%a

But all my solutions crashed with error.

My idea to pass the found file to any variable, OR give it straight forward to the extracting tool. Do you have any working solution/workaround for this? Thanks in advance!

Balázs Szakál · Accepted Answer · 2015-07-02 06:51:56Z

1

After 1.5 days i realized that DIR have built in search, that can solve my problem without the pipe:

dir /b *filename

but still really interested in your - pipe included - solution :)

edited Jul 2, 2015 at 6:51

answered Jul 1, 2015 at 14:40

Balázs Szakál

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Comments

lit · Accepted Answer · 2015-07-01 14:38:31Z

0

I am not quite sure of what you want. Does 7z produce a list of filenames?

for /f "usebackq tokens=*" %f in (`7z [args]`) do (if exist "%f" echo found file "%f")

If this is used inside a batch script, the percent characters must be doubled.

answered Jul 1, 2015 at 14:38

lit

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