'this' and 'prototype', simple function

Question

I am trying to resolve a problem but I need to understand prototype.

I was reading and I thought I got it, but I am still having some complications

function Person(name){
  this.name = name;
}

Person.prototype.greet = function(otherName){
  return "Hi " + otherName + ", my name is " + name;
}

var kate = new Person('Kate'); //name
var jose = new Person('Jose'); //otherName ???

so, is my mistake when I need to call the function ? or where is it ?

What are you trying to do? You create two instances of person, but that is all. You never call greet() on any of them? — Steve
– Steve, Commented Jul 2, 2015 at 3:07

Arun P Johny · Accepted Answer · 2015-07-02 03:08:00Z

3

The name is a property of the object instance, so you need to use this.name in the greet method.

From what I understand, you need to display Hi Jose, my name is Kate like a greeting. In that case you need to pass the other person to the greet method then you can access that persons name using object.name

function Person(name) {
  this.name = name;
}

Person.prototype.greet = function(other) {
  return "Hi " + other.name + ", my name is " + this.name;
}

var kate = new Person('Kate');
var jose = new Person('Jose');

snippet.log(kate.greet(jose));

<!-- Provides the `snippet` object, see http://meta.stackexchange.com/a/242144/134069 -->
<script src="http://tjcrowder.github.io/simple-snippets-console/snippet.js"></script>

answered Jul 2, 2015 at 3:08

Arun P Johny

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