Using Perl and LibXML to obtain sub node values when namespace is used

Question

I have the following XML as an example:

<root xmlns="http://www.plmxml.org/Schemas/PLMXMLSchema" >
    <parentNode status="Good">
        <A>
            <B>
                <C id="123" >C Node Value Here</C>
            </B>
        </A>
    </parentNode>
</root>

There are multiple parentNode nodes in my XML file (only one shown here), so I am cycling through parentNode's. Once I have one, I want to obtain attribute values 3 more levels down in the XML. My XML uses a name space and I have registed the name space in my Perl script as "plm". I can obtain the parentNode attribute value just fine using name space in my path. But when I try to navigate down to node "C" and pickup attribute "id", I am getting the following error:

XPath error : Undefined namespace prefix error : xmlXPathCompiledEval: evaluation failed

I am using the following Perl script.

use XML::LibXML;
use XML::LibXML::XPathContext;

my $filename = "namespaceissue.xml";

my $parser = XML::LibXML->new();
my $doc    = $parser->parse_file($filename);
my $xc = XML::LibXML::XPathContext->new( $doc->documentElement()  );
$xc->registerNs('plm', 'http://www.plmxml.org/Schemas/PLMXMLSchema'); 

foreach my $node ($xc->findnodes('/plm:root/plm:parentNode')) {
    my $status  = $node->findvalue('./@status');
    print "Status = $status\n";

    my $val = $node->findvalue('./plm:A/plm:B/plm:C/@title');
    print "Value = $val\n";

}

If I use no namespace on the sub-nodes ./A/B/C, the script continues with no error, but no value is assigned to $val. If I add the plm: prefix I get the namespace error. Does anybody know what I am doing wrong here? Do I have to use findnodes to first find the subnodes and then extract the value with findvalue? I tried that as well and did not have any luck.

ikegami · Accepted Answer · 2015-07-02 19:48:25Z

4

$node->findvalue('./plm:A/plm:B/plm:C/@title')

should be

$xc->findvalue('./plm:A/plm:B/plm:C/@id', $node)

Tips:

Those leading ./ are useless.

$node->findvalue('./@status')

$xc->findvalue('./plm:A/plm:B/plm:C/@id', $node)

are the same as

$node->findvalue('@status')

$xc->findvalue('plm:A/plm:B/plm:C/@id', $node)

You can use getAttribute to get an element's attribute, so
```
$node->findvalue('@status')
```
can also be accomplished more efficiently using
```
$node->getAttribute('status')
```

edited Jul 2, 2015 at 19:48

answered Jul 2, 2015 at 19:25

ikegami

391k17 gold badges291 silver badges555 bronze badges

Sign up to request clarification or add additional context in comments.

1 Comment

Brian Over a year ago

Thank You. I actually had a typo in what I published, so the following actually fixed my issue. I will have to read up some more on findvalue now. my $val = $xc->findvalue('./plm:A/plm:B/plm:C/@id', $node);

Collectives™ on Stack Overflow

Using Perl and LibXML to obtain sub node values when namespace is used

1 Answer 1

1 Comment

Your Answer

Hot Network Questions

Collectives™ on Stack Overflow

1 Answer 1

1 Comment

Your Answer

Sign up or log in

Post as a guest

Related