How to pass a tuple to a python function using lambda

Question

I have two methods max(x, y) and min(x, y) which return maximum and minimum values of the arguments passed to them respectively.

I need to make a call to each one of them using lambda function something like...

funWithNum = [lambda  x: funWithNum[0], max  ,  lambda y: funWithNum[1], min]
print funWithNum[0](1, 2)
print funWithNum[1](1, 2)

When I use print funWithNum[0](1, 2), I should get max number and when I use print funWithNum[1](1, 2), I should get min number. How do I achieve this?

The first lambda function returns itself. The second one returns max. I recommend doing some more research on what lambda is. — TigerhawkT3
– TigerhawkT3, Commented Jul 4, 2015 at 7:50
You say that max & min are methods, but in your code they look more like ordinary functions. Are they functions that you've written, or are they Python's built-in max & min functions? — PM 2Ring
– PM 2Ring, Commented Jul 4, 2015 at 8:45

Sam · Accepted Answer · 2015-07-04 07:49:21Z

7

Why does everyone always think they need lambda functions!? You don't.

>>> fwn = [max, min]
>>> fwn[0](1,2)
2
>>> fwn[1](1, 2)
1

answered Jul 4, 2015 at 7:49

Sam

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