a= [6248.570994, 5282.059503, 5165.000653, 5130.795058, 5099.376451]
one way:
a=map(int, a)
the other way:
int_a=[]
for intt in a:
int_a.append(int(intt))
above ways can print right answer,but when I want sorted I met problem:
maxx=sorted(int_a,reverse=True)[:1]*1.2
print maxx
TypeError: can't multiply sequence by non-int of type 'float'
The problem seems to be that
maxx=sorted(int_a,reverse=True)[:1]*1.2
print maxx
... produces a list, not an integer and you cannot multiply a list by a floating point number. To obtain 1.2 times the maximum element in the list using this code, the following would work:
maxx=sorted(int_a,reverse=True)[0]*1.2
print maxx
... though it would be more efficient to use:
maxx=max(int_a)*1.2
print maxx
TypeError and works, but to find the maximum element multiplied by 1.2 it would make a lot more sense to do max(int_a) * 1.2
max(int_a) would be better if the goal is to find the maximum element multiplied by 1.2.Any specific reason why you are not using max? It your statement could simply be:
print max(int_a) * 1.2
[6248, 5282, 5165, 5130, 5099]