How to add data to object when keys retrieve only 1 object? PARSE.COM SWIFT

Question

Okay I have a classNamed: "PrivateGroups". Each row in PrivateGroups contains "GroupName" and "Password". In a UIView, if the user enters the GroupName and Password and hits submit, I want to add their user objectId to that specific groupname/password entry under "members".

This is the code I have that isn't working:

var query = PFQuery(className: "PrivateGroups")

query.whereKey("privatename", equalTo: joinname.text)

query.whereKey("password", equalTo: joinpassword.text)

query.findObjectsInBackgroundWithBlock { (objects, error) -> Void in

if objects.count == 1 {

for object in objects {

query.getFirstObject().addUniqueObject(PFUser.currentUser().objectId, forKey: "members")

query.getFirstObject().saveInBackground() }}

This is what the className looks like

so if you match the "members" and "password" and press the button, i want to add the user's object id to "members"

Kyle H · Accepted Answer · 2015-07-18 00:29:24Z

1

In your loop for object in objects you shouldn't need to also call query.getFirstObject() since you already have the object. Instead, try

for object in objects {
       if let arr = object["members"]{
          if(arr.containsObject(PFUser.currentUser().objectID == false){
             arr.addObject(PFUser.currentUser().objectID)
             object.saveInBackground()
          }
       }   
}

edited Jul 18, 2015 at 0:29

answered Jul 18, 2015 at 0:00

Kyle H

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4 Comments

gooberboobbutt Over a year ago

oh my bad, that isn't the issue in my project i use query1, throughout. i edited the post to reflect that. any clue?

Kyle H Over a year ago

I thought that my just be a typo! Just to make sure, your "members" column is declared as an array in Parse, right? Also, are you getting an error message when running the code?

gooberboobbutt Over a year ago

Get a error, Cannot invoke 'add unique object' with and argument list type (String!)

Kyle H Over a year ago

Sorry, forgot addUniqueObject takes more than just one input. Changed that in my answer.

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