Adding a new line character to a variable in python [duplicate]

Question

I have the below function to get the below output

22
4444
666666

Instead i'm getting

'22\n4444\n666666\n88888888\n'

Any ideas where im going wrong?

def EvenLadder(n):
    ...:     solution = ''
    ...:     if n <= 1:
    ...:         return solution
    ...:     elif n%2 ==0:
    ...:         for i in range(2,n+1,2):
    ...:             solution += (str(i)*i)+"\n"
    ...:     else:
    ...:         n = n - 1
    ...:         for i in range(2,n+1,2):    
    ...:             solution += (str(i)*i)+"\n"
    ...:     return solution

Try doing print(EvenLadder(n)) . You are just seeing the output of repr() , when you call the function without printing or storing the result in a variable . Give some value for n , obviously. — Anand S Kumar
– Anand S Kumar, Commented Jul 19, 2015 at 12:31
Your code works fine for me, The result is the same as you wished. — omri_saadon
– omri_saadon, Commented Jul 19, 2015 at 12:32
print EvenLadder(6).__repr__() - '22\n4444\n666666\n'; print EvenLadder(6) - 22 4444 666666 — omri_saadon
– omri_saadon, Commented Jul 19, 2015 at 12:33
Take a look at stackoverflow.com/q/1436703/4014959 and stackoverflow.com/q/7784148/4014959 — PM 2Ring
– PM 2Ring, Commented Jul 19, 2015 at 12:36

enrico.bacis · Accepted Answer · 2015-07-19 12:36:01Z

4

'22\n4444\n666666\n88888888\n' is the correct string representation of the expected result. In order to actually process the newline characters you need to print it:

print EvenLadder(6)

answered Jul 19, 2015 at 12:36

enrico.bacis

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