Cannot Call __construct() Variables In PHP By Their Names

Question

I have really started to look at PHP Classes, and I can not understand why this does not work. I thought if you define a variable in the constructor you can call it by that variable name. That is not the case though(?), let me give you all an example:

class test {

    public function __construct($item) {

        $this->item= $anItem;

    }

    public function callvar() {

        //Does not work
        return $anItem;

    }

    public function callvar() {

        //Works
        return $this->item;

    }

}

So my question is, am I doing something wrong? Or must you call a __construct variable by $this->item?

Thi Tran · Accepted Answer · 2015-07-20 02:24:26Z

1

$anItem is local variable in construct function, so it isn't a variable for another method. But $this->item is property of test class so that every method in test class can access this property as a global variable

answered Jul 20, 2015 at 2:24

Thi Tran

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3 Comments

Michael Jones Over a year ago

Hmm, so there is no other to access a __contruct() variables other than with $this->item?

Thi Tran Over a year ago

Personally, I always assign class properties in __contruct() function. Ex: __contruct($p1, $p2) for $this->p1, $this->p2. Then others use $this->p1, $this->p2. __contruct() is only a method

Michael Jones Over a year ago

Hmm, that is what I have been doing. I was just wondering if there is a way to shorten it down :) Thank You

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