Syntax error near unexpected token 'elif' shell script

Question

I am facing the syntax error near unexpected token,elif error for the following code.

if [ "$1" == "abc" ]; then

   echo "abc"

elif [ "$1" == "xyz" ]; then

   echo "xyz"

else 

    echo "Unkown parameter"
    exit 0

fi

Error is: abc.sh: line 28: syntax error near unexpected token elif' abc.sh: line 28:elif [ "$1" == "xyz" ]; then

This error has been discussed. Please search in previous posts. — Shravan Yadav
– Shravan Yadav, Commented Jul 23, 2015 at 12:23
I have run that code and I'm not getting any errors: $ cat sh.sh #!/bin/bash if [ "$1" == "abc" ]; then echo "abc" elif [ "$1" == "xyz" ]; then echo "xyz" else echo "Unkown parameter" exit 0 fi $ ./sh.sh abc abc $ ./sh.sh xyz xyz $ ./sh.sh a Unkown parameter — bob dylan
– bob dylan, Commented Jul 23, 2015 at 12:39
Does using = instead of == help? (POSIX specifies = bash/etc. allow == for compatibility though.) If not then this code snippet is valid and the error lies somewhere else and/or in something that didn't paste cleanly (DOS line endings, odd non-printing characters, etc.). — Etan Reisner
– Etan Reisner, Commented Jul 23, 2015 at 12:44

user2432533 · Accepted Answer · 2017-04-15 09:27:36Z

0

Code seems alright but only point I would like to add is the OS on which you are running. The == works fine with Linux RedHat/Suse or some solaris machine but on some OS like Hpux or AIX it don't work. You should use = which is correct as you are comparing strings.

answered Apr 15, 2017 at 9:27

user2432533

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