PHP Notice: Uninitialized string offset 0

Question

I'm having an annoying PHP notice error appear since upgrading to PHP 5.4. I can see where its happening but I just don't have the expertise to correct the code and stop the notice.

PHP Notice: Uninitialized string offset: 0

Its happening on line 108 of the code which actually refers to this line: $contents[$o] = $this->unicode_entity_replace($contents[$o]);

The function in question is as follows:

class unicode_replace_entities {
        public function UTF8entities($content="") {
            $contents = $this->unicode_string_to_array($content);
            $swap = "";
            $iCount = count($contents);
            for ($o=0;$o<$iCount;$o++) {
                $contents[$o] = $this->unicode_entity_replace($contents[$o]);
               $swap .= $contents[$o];
            }
            return mb_convert_encoding($swap,"UTF-8");
        }

Any assistance or explanation would be much appreciated.

EDIT: Full code for remainder of the class below (apologies it wasn't included before):

            public function unicode_string_to_array( $string ) { //adjwilli
            $strlen = mb_strlen($string);
            $array = "";
            while ($strlen) {
                $array[] = mb_substr( $string, 0, 1, "UTF-8" );
                $string = mb_substr( $string, 1, $strlen, "UTF-8" );
                $strlen = mb_strlen( $string );
            }
            return $array;
        }

        public function unicode_entity_replace($c) { //m. perez
            $h = ord($c{0});   
            if ($h <= 0x7F) {
                return $c;
            } else if ($h < 0xC2) {
                return $c;
            }

            if ($h <= 0xDF) {
                $h = ($h & 0x1F) << 6 | (ord($c{1}) & 0x3F);
                $h = "&#" . $h . ";";
                return $h;
            } else if ($h <= 0xEF) {
                $h = ($h & 0x0F) << 12 | (ord($c{1}) & 0x3F) << 6 | (ord($c{2}) & 0x3F);
                $h = "&#" . $h . ";";
                return $h;
            } else if ($h <= 0xF4) {
                $h = ($h & 0x0F) << 18 | (ord($c{1}) & 0x3F) << 12 | (ord($c{2}) & 0x3F) << 6 | (ord($c{3}) & 0x3F);
                $h = "&#" . $h . ";";
               return $h;
            }
        }

Don't guess or make us guess, var_dump($contents, $o) to see what you're trying to work with here. — deceze
– deceze ♦, Commented Jul 29, 2015 at 12:37

oshell · Accepted Answer · 2015-07-29 12:25:54Z

1

If you use array syntax on a string such as $s[1] it will access the second letter. However, if the string is empty you will get an offset error. You could prevent this using !empty($s) or make sure you are really using an array with is_array().

answered Jul 29, 2015 at 12:25

oshell

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2 Comments

maxpovver Over a year ago

he does not access $conetnt string as an array in given code

oshell Over a year ago

you don't know about his unicode_string_to_array() function. so you cannot really say. however, I gave a solution for another case too.

maxpovver · Accepted Answer · 2015-07-29 12:40:02Z

0

How about foreach?

class unicode_replace_entities {
        public function UTF8entities($content="") {
            $contents = $this->unicode_string_to_array($content);
            $swap = "";
            $iCount = count($contents);
            foreach ($contents as $k=>$v) {
                $contents[$k] = $this->unicode_entity_replace($v);
               $swap .= $contents[$k];
            }
            return mb_convert_encoding($swap,"UTF-8");
        }

answered Jul 29, 2015 at 12:40

maxpovver

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1 Comment

BottyZ Over a year ago

Tried this and now get 'PHP Warning: Invalid argument supplied for foreach()'

BottyZ · Accepted Answer · 2015-07-29 14:16:07Z

0

I've managed to get this figured out. As pointed out by another helpful soul it was $array = ""; in unicode_string_to_array function is causing $array to be a string, not an array. It should be initialized using $array = array();

answered Jul 29, 2015 at 14:16

BottyZ

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