C# Convert dynamic object to interface

Question

namespace MyNameSpace
{
    public interface IMyInterface
    {
        string GetMethod();
    }
    public class MyClass : IMyInterface
    {
       public string GetMethod()
       {}
    }
}

//Main Program

var ruleClass = Activator.CreateInstance(Assembly.GetExecutingAssembly().FullName, "MyNameSpace.MyClass"); 
if( ruleClass != null)
{
   IMyInterface myClass = (IMyInterface)ruleClass;
   //throws exception. 
}

How can I convert ruleClass to IMyInterface type so that I can call specific methods in it?

I don't get a null value of myClass at all - I get an exception when you try to cast... — Jon Skeet
– Jon Skeet, Commented Aug 3, 2015 at 6:17
Yes. It throws an exception. UnWrap method did worked for me. — Saqwes
– Saqwes, Commented Aug 3, 2015 at 6:27
Right - please be more careful when describing what you've observed in future questions. — Jon Skeet
– Jon Skeet, Commented Aug 3, 2015 at 6:30

EZI · Accepted Answer · 2015-08-03 06:14:44Z

5

Use Unwrap method.

IMyInterface myClass = (IMyInterface)ruleClass.Unwrap();

You can create it directly too

var myClass = Activator.CreateInstance(typeof(MyClass)) as MyClass;

answered Aug 3, 2015 at 6:14

EZI

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1 Comment

Rob Over a year ago

This is the right way to fix it. CreateInstance in this case returns a ObjectHandle, not a MyClass

Joel Legaspi Enriquez · Accepted Answer · 2015-08-03 06:16:49Z

0

Have you tried this?

var ruleClass = Activator.CreateInstance(typeof(MyClass));
if (ruleClass != null)
{
    var myClass = (IMyInterface)ruleClass;
    myClass.GetMethod();
}

answered Aug 3, 2015 at 6:16

Joel Legaspi Enriquez

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Comments

Karthik · Accepted Answer · 2015-08-03 06:17:26Z

0

You can try this option as well

var typ = Type.GetType("MyNameSpace.MyClass", true);
var ruleClass = Activator.CreateInstance(typ);
        if (ruleClass != null)
        {
            IMyInterface myClass = (IMyInterface)ruleClass;
            //myClass is NULL. 
        }`

answered Aug 3, 2015 at 6:17

Karthik

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