Removing or replacing a stylesheet (a <link>) with JavaScript/jQuery

I managed to do it with:

$('link[title="mystyle"]').attr('disabled', 'disabled');

it seems this is the only way to remove the styles from memory. then I added:

$('link[title="mystyle"]').remove();

to remove the element too.

To disable your selected stylesheet:

$('link[title="mystyle"]').prop('disabled', true);

If you never want that stylesheet to be applied again, you can then .remove() it. But don’t do that if you want to be able to re-enable it later.

To re-enable the stylesheet, do this (as long as you didn’t remove the stylesheet’s element):

$('link[title="mystyle"]').prop('disabled', false);

In the code above, it is important to use .prop, not .attr. If you use .attr, the code will work in some browsers, but not Firefox. This is because, according to MDN, disabled is a property of the HTMLLinkElement DOM object, but not an attribute of the link HTML element. Using disabled as an HTML attribute is nonstandard.

no jQuery solution

if you can add id to your link tag

<link rel="stylesheet" href="css/animations.css" id="styles-animations">

document.getElementById("styles-animations").disabled = true;

if you know index position of your css file in document

document.styleSheets[0].disabled = true; // first
document.styleSheets[document.styleSheets.length - 1].disabled = true; // last

if you want to disable style by name you can use this function

/**
 * @param [string]  [styleName] [filename with suffix e.g. "style.css"]
 * @param [boolean] [disabled]  [true disables style]
 */
var disableStyle = function(styleName, disabled) {
    var styles = document.styleSheets;
    var href = "";
    for (var i = 0; i < styles.length; i++) {
        href = styles[i].href.split("/");
        href = href[href.length - 1];

        if (href === styleName) {
            styles[i].disabled = disabled;
            break;
        }
    }
};

note: make sure style file name is unique so you don't have "dir1/style.css" and "dir2/style.css". In that case it would disable only first style.

Using pure javascript:

var stylesheet = document.getElementById('stylesheetID');
stylesheet.parentNode.removeChild(stylesheet);

To remove a stylesheet:

$('link[src="<path>"]').remove();

To Replace a stylesheet:

$('link[src="<path>"]').attr('src','<NEW_FILE_PATH>');

If you want to do it only with the href attribute:

$('link[href="https://example.com/mycss.css"]').remove()

ES6 solution:

const disableStyle = styleName => {
  const styles = document.styleSheets;
  let href = "";
  for (let i = 0; i < styles.length; i++) {
    if (!styles[i].href) {
      continue;
    }
    href = styles[i].href.split("/");
    href = href[href.length - 1];
    if (href === styleName) {
      styles[i].disabled = true;
      break;
    }
  }
};

Use it like disableStyle("MyUnwantedFile.css");.

Here's both an add & remove using the disabling principle mentioned in a number of these other posts to prevent cross browser issues. Note how my add checks to see if the sheet already exists, in which case it just enables it. Also, in contrast to some answers, this is designed to work using the url to a .css file as the sole argument to the functions (insulating the client from the use of id or title attributes).

function element( id ){ return document.getElementById( id ); }

function addStyleSheet( url ){
    var id = _styleSheetUrlToId( url );
    if( !_enableStyleSheet( id ) ) {
        var link  = document.createElement("link");
        link.href = url;
        link.type = "text/css";
        link.rel  = "stylesheet"; 
        link.id   = id; 
        document.getElementsByTagName("head")[0].appendChild( link );
    }
}

function removeStyleSheet( url )
{ _enableStyleSheet( _styleSheetUrlToId( url ), false ); }

// "protected" function
function _styleSheetUrlToId( url ){ 
    var urlParts = url.split("/");
    return urlParts[urlParts.length-1].split(".")[0]
           + "-style";
}

// "protected" function
// returns if the sheet was found 
function _enableStyleSheet( id, enable ) {
    if( typeof(enable) == "undefined" ) enable = true;
    var sheet = element( id );
    if( sheet ) {
        sheet.disabled = !enable;
        return true;        
    }
    return false;
}