best way for check one variable to different numbers in JavaScript if statements

Question

i want check if random variable is equal to some numbers do something

for example i have 16 number that i want check them is equal to random number or not

var randomNum = Math.floor(Math.random() * (192 - 1+ 1) + 1)
if (randomNum == 1 ||  randomNum == 24 ||  randomNum == 25 ||  randomNum == 48 ||  randomNum == 49 ||  randomNum == 72 ||  randomNum == 73  ||  randomNum == 96 ||  randomNum == 97 ||  randomNum == 120 ||  randomNum == 121 ||  randomNum == 144 ||  randomNum == 145 ||  randomNum == 168 ||  randomNum == 169 )
{
    blnRand=true;
}
else
{
    blnRand=false;
}

It's very bad way for check my variable I wanna a short code like this:

if (randomNum == 1,24,25,48,49,72,73,96,97,120,121,144,145,168,169)
   blnRand=true;
else
   blnRand=false;

but don't work too, how can write short code for the if statement in here

T.J. Crowder · Accepted Answer · 2015-08-09 07:54:32Z

2

"Best" is subjective and depends a lot on how you're using it; you have a few choices:

A switch statement:

switch (randomNum) {
    case 1:
    case 24:
    case 25:
    //...
       blnRand = true;
       break;
    default:
       blnRand = false;
       break;
}

An array:

var answers = [1, 24, 25/*...*/];
blnRand = answers.indexOf(randomNum) !== -1;

A lookup object:

var answers = {
    1: true,
    24: true,
    25: true,
    // ...
};
blnRand = answers[randomNum] || false;

A lookup Set (ES6 and higher only):

var answers = new Set([1, 24, 25/*...*/]);
blnRand = answers.has(randomNum);

answered Aug 9, 2015 at 7:54

T.J. Crowder

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1 Comment

MojtabaSh Over a year ago

Thank you so much @T.J. Crowder, It is very short and powerful answer to my question, of course i think array way is very better than

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