I want to do this
var x=$(this).attr('id');
var y = x+1;
where x is an integer
but the value I get is x1
How do I do get the 16, if x=15?
Thanks Jean
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4id, should not start with numbers...Reigel Gallarde– Reigel Gallarde2010-07-07 11:16:18 +00:00Commented Jul 7, 2010 at 11:16
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1w3.org/TR/html401/types.html#type-nameLukeH– LukeH2010-07-07 11:23:12 +00:00Commented Jul 7, 2010 at 11:23
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4 Answers
All the answers so far are missing the radix parameter
var x=parseInt($(this).attr('id'), 10);
var y = x+1;
4 Comments
Dave Markle
That's because it's an optional parameter and defaults to 10.
LukeH
@Dave: So what value do you think
parseInt('0123') might return? developer.mozilla.org/en/Core_JavaScript_1.5_Reference/…
Dan F
@Dave - Yes, optional, defaults to 10, unless the string starts with 0. It's a deprecated feature, but it still bites people. My copy of chrome even does the deprecated thing, using this test.
Dave Markle
@LukeH: Thanks for the article. Javascript strikes again. That's awful.
var y = parseInt(x) + 1;
should do the trick.
Comments
You need to tell JavaScript it's an integer using parseInt
var y = parseInt(x) + 1;
Comments
console.log(Number("23") + 1); //24
I think you should be using Number() instead of parseInt because:
console.log(Number("23#") + 1); //NaN
console.log(parseInt("23#") + 1); //24 (I would expect a NaN)
