Java: cannot call a function with parameters

Question

I am creating a little program to find the largest number in an array. The problem is that when I call my function to check for the largest value it says that it expects a class, but that doesn't really make sense for me.

Sorry for my beginner question, but I couldn't find any help elsewhere.

Here is my current code:

package challenge;

import java.util.Scanner;

class Challenge {
    public static int findMax(int arr[], int size) {
        int maxValue = arr[0];
        for(int i = 0; i < size; i++) {
            if(arr[i] > maxValue) {
                maxValue = arr[i];
            }
        }
        return maxValue;
    }

    public static void main(String[] args) {
        int numbers[] = new int[300];
        System.out.println("Enter data: ");
        Scanner scan = new Scanner(System.in);
        for(int i = 0; i < 300; i++) {
            int input = scan.nextInt();
            numbers[i] += input;
        }
        int maxValue = findMax(numbers[], numbers.length);
        System.out.println("The largest value in the array: " + maxValue);

    }
}

Thank you and have a nice day.

I'd advise you to write int[] numbers (instead of int numbers[]), as that cleary conveys that you've got a variable named numbers of type int[] (integer-array). That does not solve your problem, but you'll be more likely to spot the error once you changed that ;) — Tedil
– Tedil, Commented Aug 15, 2015 at 17:07

Madhawa Priyashantha · Accepted Answer · 2015-08-15 16:51:21Z

1

change this

int maxValue = findMax(numbers[], numbers.length);

to this

int maxValue = findMax(numbers, numbers.length);

when you pass array to a method you should not include [] brakets.you should pass the name of array numbers not numbers[]

answered Aug 15, 2015 at 16:51

Madhawa Priyashantha

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1 Comment

Valdas Vabolis Over a year ago

Oh, thank you a lot, never knew that arguments require only the data type names.

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