PHP file upload check - it is possible before sending the input via POST?

Question

I have a very basic code to upload form:

echo "<form action='upload.php' method='post' enctype='multipart/form-data'>";
echo "Select upload:   ";
echo "<input type='file' name='fileToUpload' id='fileToUpload'>";
echo "<input type='submit' value='Upload file' name='submit'>";
echo "</form>";

Ok, now I want to check the input if the user has selected a file or not, but before sending the input filename via POST to another PHP file (upload.php)

I know that checking if no file has been selected can be done something like this:

if(!isset($_FILES['fileToUpload']) || $_FILES['fileToUpload']['error'] == UPLOAD_ERR_NO_FILE) {
    echo "Error no file selected"; 
} else {
    echo "ok";
}

I know that somehow I need the check the input here in this file:

echo '<form action="'.htmlspecialchars($_SERVER["PHP_SELF"]).'" method="post">';

But how can mix these together ? I want to pass the filename to another php file, when a file is selected.

Thank you.

you can use JS to check that file has been selected or not before submitting the data. — anuj arora
– anuj arora, Commented Aug 18, 2015 at 10:12

Kamal Kumar · Accepted Answer · 2015-08-18 10:14:36Z

1

If you want to check this with javascript you can use following

var filename = document.getElementById("DealImage").value;

if (filename != ''){
   alert('files selected');
}else{
   alert('empty files input');
}

answered Aug 18, 2015 at 10:14

Kamal Kumar

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Ashish Ranade · Accepted Answer · 2015-08-18 10:14:22Z

1

You can use jQuery to check file is selected or not on form submit.

if ( $('#fileToUpload').val() == '' || $('#fileToUpload').val() == null) {
    alert("Please select file");
}

answered Aug 18, 2015 at 10:14

Ashish Ranade

6053 silver badges14 bronze badges

1 Comment

Tass Mark Over a year ago

Thank you for the help user27715!

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