Bash args in python

Question

I need to run a code like this

dk=$(python -c "import hashlib; hashlib.sha256('$1' + 'salt').hexdigest()");
echo $dk

But it's like the '$1' is not working using 'python -c'. How to do ? :)

What do you mean by "is not working"? What results do you get? What result would you expect? — Some programmer dude
– Some programmer dude, Commented Aug 22, 2015 at 1:50
I added a echo $1 before the python and the output is : "lol" ( I chosen "lol" as password ). What I call "is not working" is that I expected that bash take my argument, then use it in the python function. The function make a sha256 salted password using a salt. But the actual output is a blank line. — Amat Erasu
– Amat Erasu, Commented Aug 22, 2015 at 2:00

mhawke · Accepted Answer · 2015-08-22 02:03:31Z

3

Try adding a print to print the hex digest to stdout:

import hashlib; print hashlib.sha256('$1' + 'salt').hexdigest()

So the shell command becomes:

$ dk=$(python -c "import hashlib; print hashlib.sha256('$1' + 'salt').hexdigest()")
$ echo $dk
532b86a29eae4a625bac7c2f0208a58b5ff08e65780917d54e027d927bc92381

Note that this uses the value of $1 in the parent's environment. If you wanted to pass a value as a command line argument you could modify the command to:

$ dk=$(python -c "import sys; import hashlib; print hashlib.sha256(sys.argv[1] + 'salt').hexdigest()" argument)
$ echo $dk
7353bc6a6fcee8b3c908bdaed02b49e6140818a0dcaf37507451b23ae6952687

edited Aug 22, 2015 at 2:03

answered Aug 22, 2015 at 1:57

mhawke

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1 Comment

Amat Erasu Over a year ago

Great ! Thanks ! Exactly what I wanted :D

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