Polymorphism in Swift (if not)

Question

I have this code in swift: To explain the idea of polymorphism!

//Polymorphism


class Person {
var name:String="Guest"
var age:Int=0

init(name:String) {
    self.name=name
    self.age=0
}
init(name:String, age:Int) {
    self.name=name
    self.age=age
}

func Update(name:String) {
    self.name=name
}
func Upgrade() {
    self.age++
}
}



class Student:Person
{
var average:Float=100
func IsOk()->Bool {
    return average > 80
}
init(name:String, average:Float) {
    super.init(name: name)
    self.average=average
}
}


class Teacher:Person {
var Salary:Float=2000
init(name:String, age:Int, Salary:Float){
    super.init(name: name, age: age)
    self.Salary=Salary

}
func GetNetSalary()->Float {
    return 0.8*self.Salary
}

override func Upgrade() {
    super.Upgrade()
    Salary*=1.1 // add 10% to salary
}
}



var t1:Teacher=Teacher(name: "Ahmed", age: 28, Salary: 3000)
var st1=Student(name:"Test", average: 70)

var p1:Person=Person(name: "abc")
var p2:Person=Student(name: "Student1", average: 100) //up casting
var p3:Person=Teacher(name: "Teacher", age: 40, Salary: 3008)


var arr=[t1, st1, p1, p2, p3] //array of persons and teachers and students

for instance in arr {
if instance is Student {println("This is student")}
if instance is Teacher {println("This is teacehr")}  
}

In the end in the for loop How could I put such a condition to see if an element in the array is only a Person? Because when I type:

if instance is Person {println("This is a Person")}

This gives me an error because this condition is always true!

possible duplicate of How do you find out the type of an object (in Swift)? — nhgrif
– nhgrif, Commented Aug 22, 2015 at 14:22
In the future, start by boiling your problem down to the absolute necessary example that duplicates your problem. This code is far from that. — nhgrif
– nhgrif, Commented Aug 22, 2015 at 14:22

Renzo · Accepted Answer · 2016-04-14 04:54:13Z

2

EDITED

You are asking:

How could I put such a condition to see if an element in the array is only a Person?

In a strongly, statically, typed language in which you cannot access the run-time type of an object, you cannot do this. However, in Swift you can use the reflexive properties of the language, through the dynamicType method, to get such a type.

edited Apr 14, 2016 at 4:54

answered Aug 22, 2015 at 19:36

Renzo

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3 Comments

Dan Rosenstark Over a year ago

Sorry, what? If the object is a Person -- and not a subclass -- it's dynamicType will reflect that. And it doesn't matter what the variable's type is...

Dan Rosenstark Over a year ago

Example of such a language in which you cannot access the run time type of an object?

Renzo Over a year ago

For instance OCaml, where type information is completely managed at compile time, and is not present at run-time.

Jafar Khoshtabiat · Accepted Answer · 2020-02-25 13:43:39Z

1

I should say that @Renzo's answer is outdated and dynamicType is deprecated. you must use type(of:) method for that. one more advice: if you want to know the exact type of an optional object, unwrap it first, then pass it to type(of:)

class A { }
class B: A { }

let b: A? = B()
print("\(type(of: b))")    // you will get optional(A)

if let temp = b {
    print("\(type(of: temp))")    // you will get(B)
}

edited Feb 25, 2020 at 13:43

answered Feb 25, 2020 at 13:25

Jafar Khoshtabiat

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Comments

pacification · Accepted Answer · 2015-08-22 16:49:36Z

0

Try this:

for instance in arr {
    if instance.dynamicType == Person.self {print("This is a Person")}
    if instance.dynamicType == Student.self {print("This is student")}
    if instance.dynamicType == Teacher.self {print("This is teacehr")}
}

More information about this you can find in Metatype Type chapter of documentation.

answered Aug 22, 2015 at 16:49

pacification

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Comments

Siam · Accepted Answer · 2015-08-22 14:22:21Z

-2

Maybe you can test if the element is aTeacher ? If not, it must be aPerson!

answered Aug 22, 2015 at 14:22

Siam

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2 Comments

nhgrif Over a year ago

If it's not a Teacher, it could be a Student. And what happens if we add a Janitor, Parent, Principal, Advisor, etc. Now all of the sudden adding code elsewhere breaks the code here, where ever this test is... plus, as the question my comment linked demonstrates, we can just check for exact class...

Siam Over a year ago

Oh, sorry, it's my fault, maybe you can compare with the class name

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