If I try to run the following code:
def func():
a = 5
print 'done'
return a
temp = raw_input('')
if temp == '':
func()
print func()
Say temp is '' and the function is run. It prints done and returns variable a. How can I print the returned variable without running the function once more, so done isn't printed again?
You should assign the returned value to a variable (e.g. a).
Update: you could either print inside the function (version1) or use global variable (version2)
def func():
a = 5
print 'done'
return a
# version 1: if print doesn't have to be outside of the function
def main():
temp = raw_input('')
if temp == '':
local_a = func()
else:
# use else to avoid UnboundLocalError: local variable 'a' referenced
# before assignment
local_a = None
print local_a
if __name__ == "__main__":
main()
# # version 2: if print have to be outside of the function, then I can only
# # think of using global variable, but it's bad.
# global_a = None
# def main():
# temp = raw_input('')
# if temp == '':
# global global_a
# global_a = func()
# if __name__ == "__main__":
# main()
# print global_a
You could use @zyxue's answer above and store the return value to a variable or you could also just not return anything from the function and just assign you final value in a function to a global variable if you have need for that. I should warn you that it isn't good practice to overuse global variables unnecessarily or overly. See: https://stackoverflow.com/a/19158418/4671205
