Selecting specific table cells in Selenium web driver (Python)

I would use lxml instead, if it is just to process hxml...

It would be helpful if you're more specific, but you can try this if you are traversing links in a webpage..

from lxml.html import parse

pdoc = parse(url_of_webpage)
doc = pdoc.getroot()
list_of_links = [i[2] for i in  doc.iterlinks()]

list_of_links will look like ['/en/images/logo_com.gif', 'http://www.brand.com/', '/en/images/logo.gif']

doc.iterlinks() will look for all links such as form, img, a-tags and yield lists containing Element object containing the tag, the type of tag (form, a or img), the url and a number, so the line

list_of_links = [i[2] for i in  doc.iterlinks()]

Note that the retrieved url is relative. As in you will see urls like

'/en/images/logo_com.gif'

instead of

'http://somedomain.com/en/images/logo_com.gif'

if you want to have the latter kind of url, add the code

from lxml.html import parse
pdoc = parse(url_of_webpage)
doc = pdoc.getroot()
doc.make_links_absolute()     #  add this line
list_of_links = [i[2] for i in  doc.iterlinks()]

If you are processing the url one by one, then simply modify the code to something like

for i in iterlinks():
    url = i[2]
    # some processing here with url...

Finally, if for some reason you need selenium to come in to get the webpage content, then simply add the following to the beginning

from selenium import webdriver
from StringIO import StringIO

browser = webdriver.Firefox()
browser.get(url)
doc = parse(StringIO(browser.page_source)).getroot()

From what we have provided at the moment, there is a table and you have the desired links in a specific column. There are no "data-oriented" attributes to rely on, but using column index to locate the links looks good enough:

for row in driver.find_elements_by_css_selector("table#myid tr"):
    cells = row.find_elements_by_tag_name("td")

    print(cells[2].text)  # put a correct index here