Checking jquery object content

Question

Does anyone know, why jquery behaves like this:

var $test = $(window).add(document).add("body");
$test.is(window) -> false
$test.is(document) -> true
$test.is("body") -> true

How do I find out whether a jquery-object contains the window via "is"?

mindfullsilence · Accepted Answer · 2015-09-11 02:54:28Z

1

var $test = $(window).add(document).add("body");
$test.is(function(index, elements) {
    return this === window;
});

the jQuery "is()" method checks the nodeType of the elements being passed. Document has a nodeType of 9. Body has a nodeType of 1. Window has no nodeType, ergo "undefined" which evaluates to false. To get around this, build your own filtering function as illustrated above.

answered Sep 11, 2015 at 2:54

mindfullsilence

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1 Comment

shoesel Over a year ago

Yeah...document and body both have the NodePrototype in their prototype chain and are "HTML-Nodes", window is completely different and extends the WindowProtptype. Thanks for the hint. Would be nice for jquery to include that.

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