Right triangle using nested for loop python 3.x

Question

I'm trying to output a right triangle with numbers. Here is what I have so far:

for i in range(1, 10):
    for j in range(i):
    print(i, end='')
print()

My output is this

My question is this. Can I make these numbers run in sequence using a nested for loop example:

I've tried about 6 other sets and mostly keep getting the same output or multiple errors. Can anyone help me out with this?

Martin Evans · Accepted Answer · 2015-09-12 12:41:02Z

1

You might want to consider what happens next? This gives you a few ideas.

import itertools

for i in range(1, 21):
    cycle = itertools.cycle([1,2,3,4,5,6,7,8,9,0])
    for j in range(i):
        print(next(cycle), end="")
    print()

This cycles through the digits giving you output as follows:

1
12
123
1234
12345
123456
1234567
12345678
123456789
1234567890
12345678901
123456789012
1234567890123
12345678901234
123456789012345
1234567890123456
12345678901234567
123456789012345678
1234567890123456789
12345678901234567890

Or alternatively:

for i in range(1, 21):
    for j in range(i):
        print(((j % 10) + 1) % 10, end="")
    print()

answered Sep 12, 2015 at 12:41

Martin Evans

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5 Comments

LiL_Cj Over a year ago

This works out perfectly. Like I said I'm still new to this language now I see in yours that 0 is actually coming up. How does that work out? because anytime I try to run 0 as part of my range I always start off with 1 instead of 0 like I'm trying for

Martin Evans Over a year ago

The first example just cycles through the digits, the second one makes use of the % modulus operator to give a remainder, e.g. 12 % 10 = 2 and 0 % 10 = 0, so add 1 and it would then cycle from 1 to 10, another % would make it cycle 1 to 0.

LiL_Cj Over a year ago

I was just getting ready to post back to you that I had figured that portion out. Thank you so much for your help on this now its starting to make a little more sense.

LiL_Cj Over a year ago

so out of curiosity why is it when I try to run a set of higher numbers in stepped count i.e. 10 11 12 13 14 15 16 17 18 19 I tried to change around the variables but either get the exact printing as before or it prints nothing but 0's. possibly need to build up a library of some type? not sure how yet but ill do some more reading tomorrow when I have the chance

LiL_Cj Over a year ago

apologies for blowing up your feed I found where my problem was after I started reading through it again. in the mad rush to develop the loop code I totally had a blond moment and forgot to add height variable into the final equation. As soon as that was input it took straight off

Yu Hao · Accepted Answer · 2015-09-12 12:19:13Z

1

j can do more than a counter:

for i in range(1, 10):
    for j in range(i):
        print(j + 1, end='')
    print()

answered Sep 12, 2015 at 12:19

Yu Hao

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1 Comment

LiL_Cj Over a year ago

thank you for your help, I can see where I need to reread a number of sections I had to have missed this

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