Understanding OOP in Actionscript

Question

A.as : 

    public class A {

    public function getFunction():Function { 
      return function():void {
        if(this is C) {
          trace("C");
        } else {
          trace("not C");
        }
     }
  }


public function func1():void {
   var internalFunc:Function = getFunction();
   internalFunc();
 }

}

B.as : 
public class B extends A implements C {

}

In some other class :

var b:B = new B();
   B.func1();

Output is : "Not C"

I was expecting the trace output to be
"C"

Can someone explain why?

back2dos · Accepted Answer · 2010-07-15 14:47:45Z

5

An anonymous function, if called directly, is scoped to the global object. If you trace this inside it, you will see [object global] instead of [object B], as you would, if this refered to b.

A common workaround is using a closure:

  var self:A = this;
  return function():void {
    if(self is C) {
      trace("C");
    } else {
      trace("not C");
    }
 }

Please note however, the instance-members of a class defining an anonymous function are available from within. This works, because they are resolved at compile time.

edit in response to Amarghosh's question:

Yes, this points to the global object, but that doesn't mean, you cannot access the instance members of the declaring class. This little piece of code should explain the details:

package  {
 import flash.display.Sprite;
 public class Test extends Sprite {
  private var foo:String = "foo";
  public function Test() {
   var anonymous:Function = function ():void {
    trace(foo);//foo
    trace(this.foo);//undefined
   };
   anonymous();
  } 
 }
}

greetz
back2dos

edited Jul 15, 2010 at 14:47

answered Jul 15, 2010 at 13:56

back2dos

15.6k36 silver badges52 bronze badges

Sign up to request clarification or add additional context in comments.

5 Comments

JeffryHouser Over a year ago

His code sample doesn't have an anonymous function, though. Here is a good write up on anonymous functions in Flex: darronschall.com/weblog/2004/08/…

Amarghosh Over a year ago

instance members will be available only if you assign this to a local variable within the enclosing function, right? Otherwise with this pointing to global, what would you use to refer to them?

back2dos Over a year ago

@www.Flextras.com : See Amarghosh's comment to your response.

JeffryHouser Over a year ago

I saw it; I must have done a bad copy and paste job when I tried to run his code.

apscience Over a year ago

So the behavior for anonymous functions is weird since it is scoped to Global but can access instance members?

JeffryHouser · Accepted Answer · 2010-07-15 14:02:11Z

1

A few things with the code that I assume are just typos?

The getFunction() method doesn't return anything and will thus cause a compiler error.
Your call code calls func1() as a static method, not as a method on an instance of the B. This will also cause a compiler error. I believe these are typos.

In my tests, using your modified code. The output is C. There must be something else going on with your code. Here are my mods to A:

    public function getFunction():Function { 
        if(this is C) {
            trace("C");
        } else {
            trace("not C");
        }
        return getFunction;
    }

Here is my mod to the runnable code, which I put in creationComplete of an empty MXML Application file:

            var b:B = new B();
            b.func1();

I assume your "real world" code is more extensive than the sample and there must be something else going on.

answered Jul 15, 2010 at 14:02

JeffryHouser

39.4k4 gold badges41 silver badges60 bronze badges

4 Comments

Amarghosh Over a year ago

He is returning an anonymous function from getFunction and calling it from func1 - this will be global as suggested by back2dos

JeffryHouser Over a year ago

I must have copied and pasted his code incorrectly when I tried to run it; as the getFunction was returning nothing.

simplfuzz Over a year ago

@flextras.com, you did not copy it incorrectly :-). I had edited my code after posting it for the first time..

JeffryHouser Over a year ago

@dta, Thanks for the clarification; good to know I'm that crazy yet. :-)

Collectives™ on Stack Overflow

Understanding OOP in Actionscript

2 Answers 2

5 Comments

4 Comments

Your Answer

Hot Network Questions

Collectives™ on Stack Overflow

2 Answers 2

5 Comments

4 Comments

Your Answer

Sign up or log in

Post as a guest

Related