Replace last number in version number using bash

Question

I have the following string in a file:

<Product Id="*" Name="NAME" Language="1033" Version="1.2.3.4" Manufacturer="Manufacturer" UpgradeCode="12345">

I want to replace the last number field in the version value (i.e. "4") using bash command (sed?) with a new number. I want to be able to change this to any other number that I pass. I tried using:

sed -i -e "s#Version=\"\([0-9]\)\.\([0-9]+\)\.\([0-9]+\)\.\([0-9]+\)\"#Version=\"\1\.\2\.\3\.10\"#g" <filename>

but this didn't work.

While it is possible to update XML using sed, it's really not the best tool for the task unless you've got nothing else. Which is unlikely, considering you're dealing with XML to begin with. — JB.
– JB., Commented Sep 15, 2015 at 9:19
I only need to change the version number within a bash script. — Wahaj Ali
– Wahaj Ali, Commented Sep 15, 2015 at 10:10

Community · Accepted Answer · 2020-06-20 09:12:55Z

3

give this sed line a try:

update

fix:

sed -r 's/(.*Version="[^"]*[.])[^."]+(".*)/\1foo\2/ file

the above line change the last 4 into foo. You just change the foo to your desired value.

edited Jun 20, 2020 at 9:12

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answered Sep 15, 2015 at 9:23

Kent

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7 Comments

Wahaj Ali Over a year ago

This doesn't always work for large number? Appends for large numbers.

123 Over a year ago

@WahajAli They didn't include the . so it only get the last character before the quotes. Use sed -r 's/(.*Version="[^"]*\.)[^."]+(".*)/\1foo\2/'

NeronLeVelu Over a year ago

This should work also fo large number. Which one failed in your test ?

NeronLeVelu Over a year ago

@９９９９９９９９９９９９９９９９９９９９９９９９９９９９９９ This is not the same, in your case you must have at least a . and not in Kent one but both works

Kent Over a year ago

@WahajAli a [.] was missing.. sorry, fixed in answer.

|

anubhava · Accepted Answer · 2015-09-15 09:26:46Z

1

If you have gnu-awk, you can do yhis:

awk -v n=8 '{print gensub(/(Version="[0-9.]+\.)[0-9]+"/, "\\1" n "\"", "1")}' file
<Product Id="*" Name="NAME" Language="1033" Version="1.2.3.8" Manufacturer="Manufacturer" UpgradeCode="12345">

Where n is the version # you want to update in the file.

answered Sep 15, 2015 at 9:26

anubhava

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Comments

NeronLeVelu · Accepted Answer · 2015-09-16 05:33:00Z

1

Assuming:

(cfr @９９９９９９９９９９９９９９９９９９９９９９９９９９９９９９) there is at least 1 dot in the version (needed to increment or modify by definition)
it have only 1 version to change by line, and line is the good one (no preselection nor separation where XML allow several "tag" per line) and not spread on several line
I use [[:alnum:]] class instead of only [[:digit:]] allowing letter in version like beta, ...

sed 's/\([[:blank:]]Version="[^"]*[.]\)[[:alnum:]]*"/\1YourNumber"/' YourFile

edited Sep 16, 2015 at 5:33

answered Sep 15, 2015 at 10:34

NeronLeVelu

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4 Comments

123 Over a year ago

If you wanted to provide a case for both if it includes a . and not you could us sed -r 's/(.*Version=")([^."]*|([^"]+\.)[^."]+)(".*)/\1\3foo\4/'

NeronLeVelu Over a year ago

i try to stay posix compliant, so reusable everywhere (no |). Without my consraint, you are right

123 Over a year ago

I thought the bar was posix compliant. It says Alternation is supported through the usual vertical bar |. on here. Also the formatting in your answer is messed up somehow.

NeronLeVelu Over a year ago

| is not a OR in posix version (nor escaped version). The sed posix is realy basic (less than grep BRE)

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