I am trying to break down my previous questions and made a plan to achieve in different steps to what I am ultimately looking for. Currently I am trying to do a loop to find out whether a mechanical system is switched on or not for each unique source as shown in first table below in source column.
For example I have been given the following profile which tells me what hours on a typical weekday the system is on for each of the 4 seasons. Please note the some sources are on more than one period during a day, hence you can see stack 2 repeated for 2 periods.
What I am trying to achieve now is that I have created some sample dates and would like to do a loop through each unique sources and just say whether for a specific hour the system is on or off based on the information provided in Profile table. So far what I have done is created the following table with the codes below:
And the code below will create the above table:
# create dates table
dates =data.frame(dates=seq(
from=as.POSIXct("2010-1-1 0:00", tz="UTC"),
to=as.POSIXct("2012-12-31 23:00", tz="UTC"),
by="hour"))
# add year month day hour weekday column
dates$year <- format(dates[,1], "%Y") # year
dates$month <- format(dates[,1], "%m") # month
dates$day <- format(dates[,1], "%d") # day
dates$hour <- format(dates[,1], "%H") # hour
dates$weekday <- format(dates[,1], "%a") # weekday
# set system locale for reproducibility
Sys.setlocale(category = "LC_TIME", locale = "en_US.UTF-8")
# calculate season column
d = function(month_day) which(lut$month_day == month_day)
lut <- data.frame(all_dates = as.POSIXct("2012-1-1") + ((0:365) * 3600 * 24),
season = NA)
lut <- within(lut, { month_day = strftime(all_dates, "%b-%d") })
lut[c(d("Jan-01"):d("Mar-15"), d("Nov-08"):d("Dec-31")), "season"] = "winter"
lut[c(d("Mar-16"):d("Apr-30")), "season"] = "spring"
lut[c(d("May-01"):d("Sep-27")), "season"] = "summer"
lut[c(d("Sep-28"):d("Nov-07")), "season"] = "autumn"
rownames(lut) = lut$month_day
dates = within(dates, {
season = lut[strftime(dates, "%b-%d"), "season"]
})
What I am trying to do now is add columns to the right for each unique values in Source column in the profile table and estimate based on the following criteria weather the system was on or off for each hour in the dataset.
I am struggling with the programming concept of how to do similar to vlookup with multiple if conditions and paste value in the new columns. For example, for my sample data the loop should create 2 programs as the Source column has only 2 unique sources Stack 1 and Stack 2. The tricky bit is the if statement with it that will need something like:
As an example the first line of the table 2 should match the value of the season column with the profile table and see if that hour falls within the period of that particular season when the system will be on. If it falls in within the stated period then say 'on' and if outside just say off. So the result should look like this 2 red font columns of the figure below:
An example day in winter:
An example day in spring:
I have managed to get the unique value of the column with the following code:
values <- unique(profile$Source)
But now its just not working with a for loop any further.
I am just wondering if anyone could give me any advise on how can I do the loop to create 2 more columns with the unique sources in table 2?
Below is the typical weekly 'profile' data table that I am using:
> dput(profile)
structure(list(`Source no` = c(1L, 1L, 1L, 1L, 1L, 1L, 1L, 2L,
2L, 2L, 2L, 2L, 2L, 2L, 2L, 2L, 2L, 2L, 2L, 2L, 2L), Source = structure(c(1L,
1L, 1L, 1L, 1L, 1L, 1L, 2L, 2L, 2L, 2L, 2L, 2L, 2L, 2L, 2L, 2L,
2L, 2L, 2L, 2L), .Label = c("Stack 1", "Stack 2"), class = "factor"),
Period = c(1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L,
1L, 1L, 2L, 2L, 2L, 2L, 2L, 2L, 2L), Day = structure(c(2L,
6L, 7L, 5L, 1L, 3L, 4L, 2L, 6L, 7L, 5L, 1L, 3L, 4L, 2L, 6L,
7L, 5L, 1L, 3L, 4L), .Label = c("Fri", "Mon", "Sat", "Sun",
"Thu", "Tue", "Wed"), class = "factor"), `Spring On` = c(0L,
0L, 0L, 0L, 0L, 0L, 0L, 6L, 6L, 6L, 6L, 6L, 6L, 6L, 15L,
15L, 15L, 15L, 15L, 15L, 15L), `Spring Off` = c(23L, 23L,
23L, 23L, 23L, 23L, 23L, 7L, 7L, 7L, 7L, 7L, 7L, 7L, 18L,
18L, 18L, 18L, 18L, 18L, 18L), `Summer On` = structure(c(1L,
1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L,
1L, 1L, 1L, 1L, 1L), .Label = "off", class = "factor"), `Summer Off` = structure(c(1L,
1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L,
1L, 1L, 1L, 1L, 1L), .Label = "off", class = "factor"), `Autumn On` = structure(c(1L,
1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L,
1L, 1L, 1L, 1L, 1L), .Label = "off", class = "factor"), `Autumn Off` = structure(c(1L,
1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L,
1L, 1L, 1L, 1L, 1L), .Label = "off", class = "factor"), `Winter On` = structure(c(1L,
1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 2L, 2L,
2L, 2L, 2L, 2L, 2L), .Label = c("0", "off"), class = "factor"),
`Winter Off` = structure(c(1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L,
1L, 1L, 1L, 1L, 1L, 1L, 2L, 2L, 2L, 2L, 2L, 2L, 2L), .Label = c("23",
"off"), class = "factor")), .Names = c("Source no", "Source",
"Period", "Day", "Spring On", "Spring Off", "Summer On", "Summer Off",
"Autumn On", "Autumn Off", "Winter On", "Winter Off"), class = "data.frame", row.names = c(NA,
-21L))
many thanks
dates = data.frame(dates =seq(as.Date('2010-01-01'),as.Date('2012-12-31'),by = "hour"))dates =data.frame(dates=seq(from=as.POSIXct("2010-1-1 0:00", tz="UTC"), to=as.POSIXct("2012-12-31 23:00", tz="UTC"), by="hour"))"if the hour same is the value in the 'season' column then look up the hour, day of the week and return if the system is switched on or not."