closedset = set()
root = (5,6)
for u,v in root:
if v is not closedset:
closedset.add(root)
print closedset
Error:
for u,v in root:TypeError: unpack non-sequence
What should i do with type of error?
-
1unpack a sequence, of course...Wayne Werner– Wayne Werner2010-07-16 13:19:45 +00:00Commented Jul 16, 2010 at 13:19
Add a comment
|
4 Answers
root = [(5,6)]
...should work. for iterates through a list or set, returning first u, then v. If you want to return both parts of the set, you'll have to add itself to a list.
Comments
I'm not sure I understand what you're trying to do. Maybe:
roots = [(5, 6), (2, 3)]
for u, v in roots:
if f not in closed:
closed.add(v)
print closed
Note a few changes:
rootsis now a list of tuples.for u, v in rootswill correctly "unpack" each tuple intouandv- by
if v is not closedyour probably meantif f not in closed, ifclosedis a dictionary of some kind - if
close.addis a method (of a set?), then it has to be called with parens()and not brackets()
1 Comment
Shilpa
Actually the problem is: keys = child.keys() - here child is a dictionary root = keys[0] - so this will return - (5,4) Now i need to iterate...for u, v values..I am doing right ?? closed is a set and the commands I used for it are: closedset = set()
root = ((5, 6),)
or
u, v = root
Depending on what your intentions are.
Comments
for u,v in [root]:
print u,v
will do what you want.
