I have this bit of code:
corpus = "T1T2T3"
for character in corpus:
if character == 'T':
print character + corpus[corpus.index(character) + 1]
I would simply like to print all of the T's and the letters that follow. In this case, it should print T1 T2 T3 -- instead only T1 T1 T1 is being printed. Any idea what might be going wrong?
Include the index in your iteration using the enumerate function:
for index, character in enumerate(corpus):
if character == 'T':
print character + corpus[index + 1]
Alternately, you can use a regular expression to look for the pattern you want:
import re
for match in re.findall('T.', corpus): # a . in the regular expression pattern means "match any character"
print match
When you do corpus.index(character) , it will always find the index of the first occurence of character , so it would always return 0.
You can instead use enumerate() to get the index as well when you iterate over the string. Example -
corpus = "T1T2T3"
for idx, character in enumerate(corpus):
if character == 'T' and (idx + 1) < len(corpus):
print character + corpus[idx + 1]
string.index gets you only the first occurrence of the character in the string. You can specify which occurrence number you want; you would have to maintain this.
Alternately, perhaps something like this is what you have in mind, stepping through by the index.
for char_pos in len(corpus):
if corpus[char_pos] == 'T':
print corpus[char_pos:char_pos+2]
