PHP 5.5: accessing a static class member of a dynamic class stored in an object

Question

We assume the following:

class a {
  public static $foo = 'bar';
}
class b {
  public $classname = 'a';
}
$b = new b();

Is it somehow (curly braces etc.) possible to access $foo directly without generating an "unexpected :: (T_PAAMAYIM_NEKUDOTAYIM)":

$b->classname::$foo //should result in "bar" not in an "unexpected :: (T_PAAMAYIM_NEKUDOTAYIM)"

I know and use the following workaround:

$c = $b->classname;
$c::$foo;

but I would like to know if it exists another nice way to do access $foo directly.

possible duplicate of accessing static methods using a variable class name (PHP) — raina77ow
– raina77ow, Commented Sep 30, 2015 at 7:09
No its no duplicate as mentioned above, since the workaround is using what is answered in the above question. — Thomas Lauria
– Thomas Lauria, Commented Sep 30, 2015 at 8:12

Narendrasingh Sisodia · Accepted Answer · 2015-09-30 07:11:58Z

1

You can do it like using variables variable like as

class a {
  public static $foo = 'bar';

  public function getStatic(){
      return self::$foo;
  }
}
class b {
  public $classname = 'a';
}
$b = new b();
$a = new a();
echo ${$b->classname}->getStatic();//bar

answered Sep 30, 2015 at 7:11

Narendrasingh Sisodia

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2 Comments

Amarnasan Over a year ago

I think the point is to get 'bar' without knowing the content of property classname in b. If you need to create a new a(), what's the point?

Thomas Lauria Over a year ago

I don't have an instance of "a" (and I can't create one because of missing constructor parameters), so your solution would not work.

Fabian Schmengler · Accepted Answer · 2015-09-30 07:42:29Z

1

For the record, the following works in PHP 7:

echo  $b->classname::$foo;

Older versions need a workaround like the one you are using (which is already the "nicest" one), because the parser worked differently.

answered Sep 30, 2015 at 7:42

Fabian Schmengler

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Comments

Amarnasan · Accepted Answer · 2015-09-30 07:27:21Z

0

You need to build this expression:

$string = a::$foo;

and you can use eval this way:

eval('$string=' . $b->classname . '::$foo;');

print($string);

answered Sep 30, 2015 at 7:27

Amarnasan

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5 Comments

Fabian Schmengler Over a year ago

OP asked for a "nice" way ;-)

Amarnasan Over a year ago

Yeah, well, I don't think he'll get it nicer than he already did, just offering alternatives.

Fabian Schmengler Over a year ago

ACK. But recommending eval goes a bit too far, don't you think?

Amarnasan Over a year ago

Guess that's up to OP to "eval" (wink, wink)

Thomas Lauria Over a year ago

I am also agreeing that eval is no nice way ;)

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