Command line argument variable @ARGV

Question

I have a task to convert script from Perl to PowerShell.

I read about command line argument of Perl: @ARGV. I understand that at the time of the script execution, any argument that is passed will be captured by this special array variable. We can read @ARGV and assign values to scalar variables using:

($var1,$var2) = @ARGV;

I need to understand what the statement below is doing:

($var1,$var2,@ARGV) = @ARGV;

In my script, I have an if condition on values in @ARGV, and based on @ARGV values, a respective subroutine is getting called.

As per my understanding if we have more than two values in @ARGV, then on left side in parenthesis statement is changing values of ARGV/used to rewrite @ARGV with remaining Values?

Ole Tange · Accepted Answer · 2015-09-30 10:54:23Z

6

It chops off the first two arguments from @ARGV and puts them in $var1 and $var2.

Personally I would have written it as:

$var1 = shift @ARGV;
$var2 = shift @ARGV;

But it is a matter of taste.

answered Sep 30, 2015 at 10:54

Ole Tange

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2 Comments

Sobrique Over a year ago

I probably wouldn't have done even that my ( $first, $second, @everything_else ) = @ARGV; is more my sort of thing :)

Brad Gilbert Over a year ago

@Sobrique There may be a call to GetOptions later in the script, which would require the modification of @ARGV.

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