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I have a table with primary keys that look like this:

FIRSTKEY~ABC

SECONDKEY~DEF

FIRSTKEY~DEF

I want to write a SELECT statement that strips off the segment following the tilde and returns all rows that are duplicates after the post-tilde segment is gone. That is,

SELECT ...

Gives me:

FIRSTKEY~ABC

FIRSTKEY~DEF

As "duplicates".

I already have the bit to strip off the end segment using SUBSTRING:

SELECT SUBSTRING(COLUMN, 0, CHARINDEX('~', COLUMN)) FROM TABLE

This is on SQL Server.

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  • So use that bit in your WHERE clause to check if both bits are equal, then return the values? Commented Jul 20, 2010 at 12:38

2 Answers 2

3

Give this a shot

SELECT SUBSTRING(COLUMN, 0, CHARINDEX('~', COLUMN)), COUNT(*) FROM TABLE 
GROUP BY SUBSTRING(COLUMN, 0, CHARINDEX('~', COLUMN))
HAVING COUNT(*) > 1
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1 Comment

This worked, but I like the answer that gives me the original rows.
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The first solution given will identify the key prefixes; extend it just a bit to get the table rows beginning with those keys:

SELECT * 
FROM TABLE
WHERE SUBSTRING(COLUMN, 0, CHARINDEX('~', COLUMN)) IN
(
    SELECT SUBSTRING(COLUMN, 0, CHARINDEX('~', COLUMN)) FROM TABLE 
    GROUP BY SUBSTRING(COLUMN, 0, CHARINDEX('~', COLUMN))
    HAVING COUNT(*) > 1
)

Alternately, you could use a join between a temp table containing the prefixes and the original table - if the number of prefixes becomes very large, using a "where in" can become very expensive.

Comments

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