Ruby Error: "no implicit conversion of Fixnum into String"

Question

I'm a beginner with Ruby, practicing looping and if statements.

I went a little off track with my course work, and tried to run the following code:

puts("Enter your age!")
age = gets.to_i
again = "Try again!"

while age <= 100 

if age == 0 
  puts("You are very very young. " + again)
  age = gets.to_i

elsif age >= 1 && age <= 5
  puts("You are quite small. Though you are breathing, you may not    understand this. " + again)
  age = gets.to_i
else 
  puts("You are a capable of reading " + again)
  age = gets.to_i
end 
end 
puts("Your age," + age + " is a good one")

When I run it, I am prompted to enter an age. If the age I enter <= 100 everything works according to the code. If not, I get the error:

rehearsal.rb:20:in +': no implicit conversion of Fixnum into String (TypeError) from rehearsal.rb:20:in'

Other StackOverflow answers (solving this error message) I read suggested that the error was in misusing the "to_i" method. I made sure to include it, and my error is still here.

Where is my bug?

Meir.r · Accepted Answer · 2015-10-02 19:32:20Z

2

In Ruby, the + method for adding strings doesn't work on integers. In your example, the age variable is an integer. This might seem a little strange if you are used to working with JavaScript.

You need to use string interpolation

puts("Your age, #{age} is a good one")

This works.

edited Oct 2, 2015 at 19:32

Meir.r

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answered Oct 2, 2015 at 19:20

Richard Hamilton

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1 Comment

Meir.r Over a year ago

It worked, with an added quotation mark at the end of the line. Thanks again!

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