Cover text() node of existing node from new node - XSLT

Question

I'm doing html to xml transformation. In html I have table like this,

<doc>
<ol>
    <li>
        <p>List<span style="color: rgb(255,0,255);">The scope of this project is to:</span></p>
        <ol>
            <li>nested list1</li>
            <li>nested <span style="color: rgb(255,0,255);">The scope of this project is to:</span> list1</li>
            <li>nested list1</li>
            <li>nested list1</li>
            <li>nested list1</li>
        </ol>
    </li>
    <li>
        <p>List<span style="color: rgb(255,0,255);">The scope of this project is to:</span></p>
    </li>
    <li>
        <p>List<span style="color: rgb(255,0,255);">The scope of this project is to:</span></p>
    </li>
</ol>

Here I need to transform html elements names to certain xml elements name and should cover the text content by <para> element.

SO my output should be,

<doc>
    <oli>
        <listitem><para>List<style type="color: rgb(255,0,255);">The scope of this project is to:</style></para>
            <oli>
                <listitem><para>nested list1</para></listitem>
                <listitem><para>nested <style type="color: rgb(255,0,255);">The scope of this project is to:</style> list1</para></listitem>
                <listitem><para>nested list1</para></listitem>
                <listitem><para>nested list1</para></listitem>
                <listitem><para>nested list1</para></listitem>
            </oli>
        </listitem>
        <listitem><para>
            List<style type="color: rgb(255,0,255);">The scope of this project is to:</style>
        </para></listitem>
        <listitem><para>
            List<style type="color: rgb(255,0,255);">The scope of this project is to:</style>
        </para></listitem>
    </oli>
</doc>

I have written following xsl to transform html to xml,

<xsl:template match="ol">
        <oli>
            <xsl:apply-templates/>           
        </oli>
    </xsl:template>

    <xsl:template match="li">
        <listitem>
            <para>
                <xsl:apply-templates/>
            </para>
        </listitem>
    </xsl:template>

    <xsl:template match="span">
        <style type="{@style}">
            <xsl:apply-templates/>
        </style>
    </xsl:template>

    <xsl:template match="p">
        <para>
            <xsl:apply-templates/>
        </para>
    </xsl:template>

    <xsl:template match="li/p">
        <xsl:apply-templates/>
    </xsl:template>

The problem I have is when ul contain nested list, li text that has contain nested list is not correctly covered with <para> element.

in above example currunt output that I'm getting for nested list is follwos,

<listitem><para>
            List<style type="color: rgb(255,0,255);">The scope of this project is to:</style>
            <oli>
                <listitem><para>nested list1</para></listitem>
                <listitem><para>nested <style type="color: rgb(255,0,255);">The scope of this project is to:</style> list1</para></listitem>
                <listitem><para>nested list1</para></listitem>
                <listitem><para>nested list1</para></listitem>
                <listitem><para>nested list1</para></listitem>
            </oli>
        </para></listitem>

so simply, instead of

<listitem><para>
                List<style type="color: rgb(255,0,255);">The scope of this project is to:</style>
                <oli>
              ........
                </oli>
             </para>
 </listitem>

I need,

    <listitem><para>
           List<style type="color: rgb(255,0,255);">The scope of this project is to:</style>
           </para>
                    <oli>
                  ........
                    </oli>

     </listitem>

I tried to cover text() content of li element by <para> but then <span> elements are not coming to the output.

Can anyone suggest a method how can I do this..

potame · Accepted Answer · 2015-10-05 07:25:40Z

1

I would simply change the template:

<xsl:template match="li/p">
    <xsl:apply-templates/>
</xsl:template>

to:

<xsl:template match="li[p]">
   <listitem>
     <xsl:apply-templates/>
   </listitem>
</xsl:template>

This template will match an <li> that contains a <p>. In this case, you don't have to add some <para>. For the <li>s that contain some <p>, the other template will match, and it does output the desired <para>.

Alternatively, you can also do something like this:

discard the template <xsl:template match="li/p">

modify the template <xsl:template match="li"> like follows:

<xsl:template match="li">
  <xsl:choose>
    <xsl:when test="p">
      <listitem>
        <xsl:apply-templates/>
      </listitem>
    </xsl:when>
    <xsl:otherwise>
      <listitem>
        <para>
          <xsl:apply-templates/>
        </para>
      </listitem>
    </xsl:otherwise>
  </xsl:choose>
</xsl:template>

edited Oct 5, 2015 at 7:25

answered Oct 5, 2015 at 7:17

potame

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