Regex PHP, Find characters in specific position

Question

I explain my problem : I'm working on different kind of address

" 25 Down Street 15000 London "

" 25 B Down Street 15000 London "

" Building A 25 Down Street 15000 London "

I found a way to determine which is the number of the street on all case with this regex :

 `^([1-9][0-9]{0,2}(?:\s*[A-Z])?)\b`

But now i got a problem that i can't solve, i need when the case is real to determine characters which are before the street's number .

Example : " Building 2 25 Down Street 15000 London " i need here to find only "Building 2"

I understand that i have to find characters before the first number of this string.

Keep searching on my own but will be great if someone got a solution for me .

Thank you .

Edit my code now is :

preg_match('/^(.*?)\d+\s+\D+/', $cleanAdressNode, $result, PREG_OFFSET_CAPTURE,0);
        print $result[0][0];

        return $result[0][0];

and the result now is : Résidence Les Thermes 1 15 boulevard Jean Jaurès instead of only : Résidence Les Thermes 1

Matching addresses using regular expressions is near impossible... it would take a purpose-built system to figure out what each token in the string means. — Sverri M. Olsen
– Sverri M. Olsen, Commented Oct 5, 2015 at 14:30

Toto · Accepted Answer · 2015-10-05 14:11:25Z

1

How about:

preg_match('/^(\D*)/', $str, $match);

You will find in $match[1] everything that is not a digit at the begining of the string.

According to your example:

preg_match('/^(.*?)\d+\s+\D+/', $str, $match);

edited Oct 5, 2015 at 14:11

answered Oct 5, 2015 at 14:02

Toto

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3 Comments

VERYNET Over a year ago

I found a way to do it look at this : regex101.com/r/nU5tA7/1 But my new problem is that i can have special characters like "é" or "ç" and my regex don't work anymore with this look at this example : regex101.com/r/yB1hI0/1 maybe you can help me with this ?

Toto Over a year ago

@VERYNET: I can't help you without seeing your code. Edit your question add the relevant part of the code, some sample input strings and expected result.

Toto Over a year ago

@VERYNET: the result is in the first group ie. $result[1][0]

Aaron · Accepted Answer · 2015-10-05 14:08:24Z

0

If you only want to match the first non-numeric characters, ^([^0-9]*) should do the trick. It uses class negation to grab every non-numeric characters at the start of the string.

answered Oct 5, 2015 at 14:08

Aaron

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9 Comments

VERYNET Over a year ago

I found a way to do it look at this : regex101.com/r/nU5tA7/1 But my new problem is that i can have special characters like "é" or "ç" and my regex don't work anymore with this look at this example : regex101.com/r/yB1hI0/1 maybe you can help me with this ?

Aaron Over a year ago

Here you're looking for the two groups "Résidence les Thermes 1" and "25 B Boulevard Emile Zola 13100 Aix en Provence" right?

VERYNET Over a year ago

Only for : "Résidence les Thermes 1" , it's the only match

Aaron Over a year ago

The 1 really is problematic, as there is no formal way to distinguish it from the street number... Let me think about it

VERYNET Over a year ago

It's seems to be resolved look at @Toto edit it works pretty well .

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