Batch - How to replace string in a %%variable

Question

I need to create a .bat file that might be very easy but I am having a real hard time trying to figure out how to do it.

I need a batch that gets all the files *.ui in the current folder, and executes a program passing two arguments to it: that *.ui file name, and the same file name with this two modifications

Added ../ in front so the referenced file is in the parent folder
Replaced file extension from *.ui to *.py

In pseudo:

for every file *.ui in this folder as file:
    file2 = "../" + replace( file, ".ui", ".py")
    execute python.exe file -o file2

This is the final .bat, but the replacing extensions part is missing:

FOR %i IN (*.ui) DO python -m PyQt4.uic.pyuic %i -o (????)

I have tried the batch replacing (????) with the file name manually and it works. But how can I add ../ and replace .ui to .py?

Thank you!

Stephan · Accepted Answer · 2015-10-06 16:22:28Z

2

FOR %i IN (*.ui) DO python -m PyQt4.uic.pyuic %i -o ..\%~ni.py

see for/?

answered Oct 6, 2015 at 16:22

Stephan

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4 Comments

mesafria Over a year ago

Hi, sorry but I don't understand your answer. What do you mean with see for/?. I tried the script and it throws an error. Sorry if this is too newbie for you, but if you could help me with this i would appreciate it very much.

Stephan Over a year ago

What does for %i in (*.bat) do @echo ..\%~ni.py say? (if you use it in a batchfile, double the %: %%i and ..\%%~ni.py)

aschipfl Over a year ago

This prepends ..` although ../` was requested -- this might cause trouble with Python...?

Stephan Over a year ago

I don't have phyton. Command repetition is fine: ..\filename.py. Ideas: a) doubling the backslash, b) enclose in quotes: "..\%~ni"

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