Javascript returning out of a function inside a function

Question

Given this code:

var x=5;
var fx=function(){
    console.log("hey");
    (function(){
        if (x==5){
            console.log('hi');
            return;
        }
    })();
    console.log('end');
};

fx();

How do I return in such a way that the final console.log is not executed when x==5?

I am new to javascript, so maybe I missed something...

This is just a case I made up, to use as an example for more complicated code I'm working on, but which follows a similar pattern. — Academiphile
– Academiphile, Commented Oct 7, 2015 at 7:42

Arun P Johny · Accepted Answer · 2015-10-07 07:38:21Z

1

You can't return like that, instead you can use a flag or make the inner function to return a value like

var x = 5;
var fx = function() {
  snippet.log("hey");

  var flag = (function() {
    if (x == 5) {
      snippet.log('hi');
      return false;
    }
  })();
  //if the returned value is false then return
  if (flag === false) {
    return
  }
  snippet.log('end');
};

fx();

<!-- Provides the `snippet` object, see http://meta.stackexchange.com/a/242144/134069 -->
<script src="http://tjcrowder.github.io/simple-snippets-console/snippet.js"></script>

answered Oct 7, 2015 at 7:38

Arun P Johny

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Comments

Dyrandz Famador · Accepted Answer · 2015-10-07 07:48:41Z

1

you can wrap your function to a condition

var x=5;
var fx=function(){
   console.log("hey");
   if( !(function(){
       if (x==5){
           console.log('hi');
           return true;
       }
    })() ){
       console.log('end');
    }
};

fx();

JSFIDDLE DEMO

answered Oct 7, 2015 at 7:48

Dyrandz Famador

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Comments

orllando · Accepted Answer · 2015-10-07 07:41:27Z

0

var x = 5;
var fx = function() {
  console.log("hey");

  if (x == 5) {
    console.log('hi');
    return;
  }

  console.log('end');
};

fx();

answered Oct 7, 2015 at 7:41

orllando

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Comments

Jacob · Accepted Answer · 2015-10-07 07:42:34Z

0

you can either an if statement or else depending on hwta you're trying to do

if

var x=5; var fx=function(){
    console.log("hey");
    (function(){
        if (x==5){
            console.log('hi');
            return;
        }
    })();
    if(x != 5){
        console.log('end');
    } };

fx();

else

var x=5;
var fx=function(){
    console.log("hey");
    (function(){
        if (x==5){
            console.log('hi');
            return;
        } else {
            console.log('end');
        }
    })();
};

fx();

answered Oct 7, 2015 at 7:42

Jacob

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