I am new to regular expression module. I am trying to remove all the links in a given exampleString but in one line of code:
exampleSentence = exampleSentence.replace(link for link in re.findall(r'http://*',exampleSentence),'')
But I am getting this syntax error:
SyntaxError: Generator expression must be parenthesized if not sole argument
How to proceed with this?
You have many issues.
First, str.replace() replace a sub-string by another in a given string; it does not take generators.
Example:
print 'example'.replace('e', 'E')
Next, if you want to remove, there is re.sub():
data = re.sub(
r'[A-Za-z]+://[A-Za-z0-9-_]+.[A-Za-z0-9-_:%&;\?#/.=]+', # the URI
'', # the replacement (nothing here)
input_data
)
The URI regex was copied from @miko-trueman answer.
If all you want to do is remove all links from a string, you don't need a generator. The following will work.
import re
exampleString = "http://google.com is my personal library. I am not one for http://facebook.com, but I am in love with http://stackoverflow.com"
exampleString = re.sub(r"(?:\@|https?\://)\S+", '', exampleString)
