str = "sysparm_type=list_data&count=20&start=0&p=incident%3Bq%3Aactive%3Dtrue%5Epriority%3D1%5EEQ&table=incident"
I've written a regex for the above string but i want to match it only if the "priority" substring is not present. Here's my regex:
.*sysparm_type=list_data&count=(\d+)&start=(\d+)&p=incident.*active.*true^((?!priority).)*$&table=incident
But this part ^((?!priority).)*$ of the regex isn't working.
Caret ^ and $ match at the beginning and end of the entire string. Very greedy.
Wouldn't it be simpler, easier to read and maintain if you just checked for the profile string to be present?
String pattern = "((?!priority).)*"; <== pasted from above, prob not valid regex
// Create a Pattern object
Pattern r = Pattern.compile(pattern);
// Now create matcher object.
Matcher m = r.matcher(line);
if (m.find( )) {
System.out.println("Found value" );
} else {
System.out.println("NO MATCH");
}
(a) regexp is bad solution for query string parsing - slow, memory consuming, error prone
(b) try to use any existing library for this task, e.g. apache commons:
String str = "sysparm_type=list_data&count=20&start=0&p=incident%3Bq%3Aactive%3Dtrue%5Epriority%3D1%5EEQ&table=incident";
List<NameValuePair> pairs = URLEncodedUtils.parse(str, StandardCharsets.UTF8)
for (NameValuePair pair : pairs)
if (pair.getName().equals("priority"))
return; // do nothing
If you want to check subString a simple solution will be checking str.indexOf(subString) will return a int if it's greater than 0 then str contains subString.
If you want to do it in regExp use the pattern .*priority.*, you can some more restriction of the substring if you're sure about its occurrences and position
^and$from the tempered greedy token.priorityis present in the keys?split).