How I can post a String from View to the Controller in ASP.NET MVC 5?

Question

net mvc 5 and have a view "Search.cshtml" and a controller "HomeController" and a model "user".

I try to create a DataTable out of Active Directory and show this in a table in the view.

I can show the table in the view but i want to implement a search textfield for selection a value in this table.

For this I create a method for testing and have the Method in my controller:

public ActionResult Search(string searchString){
    var data = GetTable(searchstring);
    return View(data);
}

static DataTable GetTable(string data){
   //...here i get data from the active Directory and filter with data parameter
}

And here is my View

<h2>Suchen</h2>

@using(HTML.BeginForm()){

   @Html.TextBox("SearchString") 

   <input type="submit" value="Suchen">

   <table>
     <thead>
       <tr>
         @foreach(DataColumn col in MOdel.Columns){
                     <th>@col.ColumnName</th>
         }
       </tr>
     </thead>
     <tbody>
      @foreach(DataRow col in Model.Rows){
         <tr>
           @foreach(DataColumn col in Model.Columns){
            <td>@row[col.columnName]</td>
           }
         </tr>
       }
     </tbody>
   </table>

}

How I can post my SearchString to my Controller and then I know wht i must do ;)

Try using the exact same name for the textbox as in the controller searchString (LowerCase s) — Dumisani
– Dumisani, Commented Oct 9, 2015 at 10:41

Andrei · Accepted Answer · 2015-10-09 10:43:53Z

1

Just specify action and controller name in the BeginForm method:

@using(Html.BeginForm("Search", "Home")){

Also I believe parameter names are case sensitive, so make sure textbox name corresponds to that of action parameter:

@Html.TextBox("searchString")

Assuming you do not have any special routing setup, that should do it - when user clicks submit button, "Search" action should get triggered.

answered Oct 9, 2015 at 10:43

Andrei

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