why I still don't get an empty array?

Question

Quoted from here:

If delimiter contains a value that is not contained in string and a negative limit is used, then an empty array will be returned, otherwise an array containing string will be returned.

But why I still don't get an empty array?

var_dump(explode(',', '', -1))

I get this:

array(1) {
  [0]=>
  string(0) ""
}

UPDATE

Try it in windows,with PHP 5.2.8 (cli) (built: Dec 8 2008 19:31:23)

why you are looking for empty array from such a expression? there is an easy way- $arr=array(); — Sadat
– Sadat, Commented Jul 22, 2010 at 7:51

Markus Hedlund · Accepted Answer · 2010-07-22 08:16:46Z

1

I can confirm that this doesn't work in PHP 5.2.8.

It does work in PHP 5.2.11. In my opinion, there are many bugs in the 5.2 branch, so try always to use the latest version. 5.3 is more stable in my experience.

answered Jul 22, 2010 at 8:16

Markus Hedlund

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Trurl123 · Accepted Answer · 2010-07-22 07:44:05Z

0

I've tried this example and got empty array. Wrong question.

answered Jul 22, 2010 at 7:44

Trurl123

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2 Comments

Sadat Over a year ago

Trurl, it results array(1) { [0]=> string(0) "" } which is non-empty

Trurl123 Over a year ago

Please use latest PHP version. May be this is a bug

Macmade · Accepted Answer · 2010-07-22 07:55:45Z

0

Tested your code, and it does return an empty array: array(0) { }.
Running PHP 5.2.11.

Maybe there's an issue with your PHP version. Can you tell us which one you are running?

answered Jul 22, 2010 at 7:55

Macmade

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