Using Jquery to get numeric value which is in between "/" in link

Question

I am trying to fetch numeric value from link like this.

Example link

/produkt/114664/bergans-of-norway-airojohka-jakke-herre

So I need to fetch 114664.

I have used following jquery code

jQuery(document).ready(function($) {
    var outputv = $('.-thumbnail a').map(function() {
        return this.href.replace(/[^\d]/g, '');
    }).get();
    console.log( outputv );
});

https://jsfiddle.net/a2qL5oyp/1/

The issue I am facing is that in some cases I have urls like this

/produkt/114664/bergans-of-norway-3airojohka-3jakke-herre

Here I have "3" inside text string, so in my code I am actually getting the output as "11466433" But I only need 114664

So is there any possibility i can get numeric values only after /produkt/ ?

I used this: /^[a-zA-Z\/]+(\d+)/ and it worked on some testing sites. Hopefully that helps — OliverRadini
– OliverRadini, Commented Oct 12, 2015 at 12:50

styke · Accepted Answer · 2015-10-12 12:47:28Z

6

If you know that the path structure of your link will always be like in your question, it's safe to do this:

var path = '/produkt/114664/bergans-of-norway-airojohka-jakke-herre';
var id   = path.split('/')[2];

This splits the string up by '/' into an array, where you can easily reference your desired value from there.

answered Oct 12, 2015 at 12:47

styke

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2 Comments

user3550203 Over a year ago

yes the url structure will always start from /produkt/{NUMERIC_VALUE}/{OTHER VALUES} So I need the numeric values in between /produkt/ and /other_values

styke Over a year ago

Cool, but be careful - the string must start with a / for the the index [2] to be right. If not, the correct index in this case would be [1].

Amit · Accepted Answer · 2015-10-12 12:48:57Z

0

If you want the numerical part after /produkt/ (without limitiation where that might be...) use a regular expression, match against the string:

var str = '/produkt/114664/bergans-of-norway-3airojohka-3jakke-herre';
alert(str.match(/\/produkt\/(\d+)/)[1])

(Note: In the real code you need to make sure .match() returned a valid array before accessing [1])

answered Oct 12, 2015 at 12:48

Amit

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