Extremly simple C program,why I am getting output like this?

Question

Code:

#include <stdio.h>
int main()
{
  long cn=1;
  char ch;
  while((ch=getchar())!=EOF)
  {
    printf("%ld\t%c\n",cn++,ch);
  } 
}

When I input word "secret" and hit enter it shows count up to 7 and not 6,why?

EOF must differ from any character! Thus getchar returns int, not char. Enable compiler warnings and take them seriously! — too honest for this site
– too honest for this site, Commented Oct 12, 2015 at 13:30
Why must the variable used to hold getchar's return value be declared as int? — phuclv
– phuclv, Commented Oct 12, 2015 at 13:51

Bart Friederichs · Accepted Answer · 2015-10-12 13:01:42Z

11

Because the "enter" character is read as well. This is in fact a "newline", ASCII code 10 (or hex 0A).

answered Oct 12, 2015 at 13:01

Bart Friederichs

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1 Comment

Thank you,I was making reading Ritchie C book and making a quiz for www.embeddedfunda.com