django Url endswith regex in url path

Question

I need to support following urls in single url regex.

/hotel_lists/view/
/photo_lists/view/
/review_lists/view/

how to support all above urls in single views?

I tried something like below

url(r'^\_lists$/(?P<resource>.*)/$', 'admin.views.customlist_handler'),

edit: hotel,photo, review is just example. that first part will be dynamic. first part can be anything.

karthikr · Accepted Answer · 2015-10-12 17:05:51Z

2

If you wish to capture the resource type in the view, you could do this:

url(r'^(?P<resource>hotel|photo|review)_lists/view/$', 'admin.views.customlist_handler'),

Or to make it more generic,

url(r'^(?P<resource>[a-z]+)_lists/view/$', 'admin.views.customlist_handler'), #Or whatever regex pattern is more appropriate

and in the view

def customlist_handler(request, resource):
    #You have access to the resource type specified in the URL.
    ...

You can read more on named URL pattern groups here

edited Oct 12, 2015 at 17:05

answered Oct 12, 2015 at 17:00

karthikr

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2 Comments

Hari Krishnan Over a year ago

first part of url , hotel, review, photo is just example. some other resource will also be start with. can you suggest how to do?

karthikr Over a year ago

Check the edit.. The second URL pattern in the answer addresses exactly that. Note that I am assuming that the resource has only lowercase alphabets. You can modify the regex pattern to accommodate your usecase. .

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