Get latitude and longitude from zip code using PHP

Question

I have a PHP page containing the following code to get latitude and longitude from a user input postal code.

But when I tried to echo the latitude and longitude, nothing is shown.

<?php
    function getLnt($zip){
    $url = "http://maps.googleapis.com/maps/api/geocode/json?address=".urlencode($zip)."&sensor=false";
    $result_string = file_get_contents($url);
    $result = json_decode($result_string, true);
    return $result['results'][0]['geometry']['location'];
    }

    getLnt("750341");
?>
<!DOCTYPE html>
<html lang="en">
    <head>
        <meta charset="utf-8" />
        <title></title>
    </head>
    <body>
        <?php
         $val = getLnt('90001');
         echo "Latitude: ".$val['lat']."<br>";
         echo "Longitude: ".$val['lng']."<br>";
        ?>
    </body>
</html>

The google result of your zipcode 750341 returns the below content { "results" : [], "status" : "ZERO_RESULTS" }. So if google returns nothing I think we can't manipulate it. — Dhay
– Dhay, Commented Oct 14, 2015 at 12:31
I've tested your code and I get Latitude: 33.9697897 Longitude: -118.2468148 as output. — Pedro Lobito
– Pedro Lobito, Commented Oct 14, 2015 at 12:31
Do a var_dump($result_string); right after, $result_string = file_get_contents($url); what does it show ? — Pedro Lobito
– Pedro Lobito, Commented Oct 14, 2015 at 12:45

sohan verma · Accepted Answer · 2018-06-11 12:37:14Z

3

Please add key parameter in api request. Key value you need to replace with google API key.

$url = "https://maps.googleapis.com/maps/api/geocode/json?address=".urlencode($postal_code)."&sensor=false&key=googleapi";
    $result_string = file_get_contents($url);
    $result = json_decode($result_string, true);
    if(!empty($result['results'])){
        $zipLat = $result['results'][0]['geometry']['location']['lat'];
        $ziplng = $result['results'][0]['geometry']['location']['lng'];
    }

answered Jun 11, 2018 at 12:37

sohan verma

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Comments

Pedro Lobito · Accepted Answer · 2015-10-14 12:51:52Z

2

I've tested your code and it works perfectly, my guess is that you've exceeded your daily quota for the Google Places API Web Service.
A quick solution is to apply for a key at:

https://console.developers.google.com/

answered Oct 14, 2015 at 12:51

Pedro Lobito

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Comments

Abderrahim Soubai-Elidrisi · Accepted Answer · 2018-01-31 12:20:48Z

1

I think your problem is on API call must be on HTTP So change http to https

<?php
    function getLnt($zip){
    $url = "https://maps.googleapis.com/maps/api/geocode/json?address=".urlencode($zip)."&sensor=false";
    $result_string = file_get_contents($url);
    $result = json_decode($result_string, true);
    return $result['results'][0]['geometry']['location'];
    }

    getLnt("750341");
?>

answered Jan 31, 2018 at 12:20

Abderrahim Soubai-Elidrisi

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Comments

Hoangnm · Accepted Answer · 2019-10-24 10:39:26Z

1

Not sure when but in 2019, we can use components in instead of address to get more accurary result. eg: country is US and postal code is 41000

$url = "https://maps.googleapis.com/maps/api/geocode/json?components=" . urlencode('country:US|postal_code:41000') . "&key=YOUR_API_KEY";

answered Oct 24, 2019 at 10:39

Hoangnm

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Comments

Avinash Singh · Accepted Answer · 2019-04-03 08:55:59Z

0

    function getLnt($zip){
    $url = "https://maps.googleapis.com/maps/api/geocode/json?address=".urlencode($zip)."&sensor=false&key=YOUR_KEY";
    $result_string = file_get_contents($url);
    $result = json_decode($result_string, true);
    return $result['results'][0]['geometry']['location'];
    }

  print_r(getLnt("462021"));

edited Apr 3, 2019 at 8:55

Avinash Singh

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answered Apr 3, 2019 at 8:16

steve

1

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