Sorting an array twice [duplicate]

Question

I have the following array:

var array = [{
    "name": "Item 1",
    "LineNumber": "10",
    "size": "5"
    },
    {
    "name": "Item 2",
    "LineNumber": "30",
    "size": "5"
    },
    {
    "name": "Item 3",
    "LineNumber": "30",
    "size": "4"
    },
    {
    "name": "Item 4",
    "LineNumber": "20",
    "size": "5"
    }]

Using the following, I am able to sort by line number:

      array.sort(function(a, b) {
        return a.LineNumber - b.LineNumber;
      });

In some situations with large data, I run into an issue where items will share the same line number, but their size will be different (ie. Item 2 and Item 3). I would like to first sort by the line number, and then order by size based on how the first sort is returned. Is it possible to achieve this in one sort compare function?

Do the first comparison, if they are equal fallback to a second comparison test and return that. — MinusFour
– MinusFour, Commented Oct 16, 2015 at 15:29

Sarjan Desai · Accepted Answer · 2015-10-16 15:33:02Z

7

Try this:

array.sort(function(a, b) {
  if (a.LineNumber == b.LineNumber)
    return a.size - b.size;
  return a.LineNumber - b.LineNumber;
});

edited Oct 16, 2015 at 15:33

Sarjan Desai

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answered Oct 16, 2015 at 15:29

0FiRE0

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Comments

Schleis · Accepted Answer · 2015-10-16 15:29:55Z

0

You just need to add more logic to your sort function.

  array.sort(function(a, b) {
    if (a.LineNumber === b.LineNumber) {
         return a.size - b.size;
    }
    return a.LineNumber - b.LineNumber;
  });

answered Oct 16, 2015 at 15:29

Schleis

44.2k8 gold badges73 silver badges90 bronze badges

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