The match function not working in Java

Question

I am doing some match functions with the Java. I have some string like this park,reserved_parking etc.. If i search for the word park like this

if(input.trim().contains ("Park"))
dummies = dummies + "   1";
else 
dummies = dummies + "   0";

It prints the values for reserved_parking also. I don't know how to find the exact match in Java. any help will be appreciated.

ya my problem is if i check for park it prints reserved_parking also — arun abimaniyu
– arun abimaniyu, Commented Oct 20, 2015 at 9:55
@arunabimaniyu, title is wrong. contains is doing its work, but your need is different. — Harshit
– Harshit, Commented Oct 20, 2015 at 9:56
@HarshitShrivastava I didn't understand his question. That is why I asked. — marstran
– marstran, Commented Oct 20, 2015 at 9:56

Aron_dc · Accepted Answer · 2015-10-20 10:00:36Z

2

Contains does what it says. It tests if the String you give as input, is somewhere in the String you test against. So "batteryparkhorsewidow".contains("park") will return true.

What you are looking for may be the equals method. This method tests for String equality. So it will only return true if your String is "park" nothing more, nothing less.

Please mind that equals works case sensitive. For a case insensitive equality check use equalsIgnoreCase

edited Oct 20, 2015 at 10:00

answered Oct 20, 2015 at 9:55

Aron_dc

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Comments

Ankur Singhal · Accepted Answer · 2015-10-20 09:57:52Z

You might need to go for case in-sensitive search,

change both the input and matched String to Upper case/lower case and then match

.

Input - park

public static void main(String[] args) {
        String input = "park";
        if (input.trim().toUpperCase().contains("Park".toUpperCase()))
            dummies = dummies + "   1";
        else
            dummies = dummies + "   0";

        System.out.println(dummies);
    }

Output

Input - reserved_parking

public static void main(String[] args) {
        String input = "reserved_parking";
        if (input.trim().toUpperCase().contains("Park".toUpperCase()))
            dummies = dummies + "   1";
        else
            dummies = dummies + "   0";

        System.out.println(dummies);
    }

Output

kanly · Accepted Answer · 2015-10-20 10:00:02Z

0

It seems a case issue. You can lowercase or uppercase the string before checking it.

input.trim().toUpperCase().contains("PARK")

Or use some external library like Apache Commons Lang's containsIgnoreCase

StringUtils.containsIgnoreCase(input, "Park");

answered Oct 20, 2015 at 10:00

kanly

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Comments

javatutorial · Accepted Answer · 2015-10-20 10:05:37Z

0

To find an exact match, you will need a Regular Expression, like this:

private boolean isMatching(String source, String stringToSearch){
     String pattern = "\\b" + stringToSearch + "\\b";
     Pattern p = Pattern.compile(pattern);
     Matcher m = p.matcher(source);
     return m.find();
}

The \b option in the regular expression means "word bonduary". So, this will match exactly "Park" if you pass that as a parameter in the stringToSearch, but it won't match "reserved_parking", returning false.

answered Oct 20, 2015 at 10:05

javatutorial

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1 Comment

Aron_dc Over a year ago

For finding exact matches a regular expression is a bit over the top, isn't it?

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